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Chemistry: Post your doubts here!

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Assalamwa'laikum Warahmatullahi Wa Baraqaatuhu...

I AM GIVING CHEM P21 THIS COMING 21st
I am giving AS levels...


i have question it does not involve past paper though....

1. Construct ionic half equation for:
a) PbO2(s) being reduced to PbSO4(s) in presence of of H2SO4(aq)
b) PbSO4(s) being reduced to Pb(s) in the presence of water.
c) Mow write the balanced equation for the reaction between PbO2 and lead in the presence of dilute sulfuric acid.

please someone EXPLAIN me the steps involved in getting the answer right...

THANK YOU!
 
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Does the addition of HCN in the presence of NaCN to an aldehyde or ketone take place under room conditions or heat under reflux? My notes say the latter but the marking schemes say the former and I'm confused..
 
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It occurs at room temperature whereas hydrolysis of CN occurs with heat under reflux. Btw post link to marking scheme.
 
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i am re-posting this question:

Assalamwa'laikum Warahmatullahi Wa Baraqaatuhu...

I AM GIVING CHEM P21 THIS COMING 21st
I am giving AS levels...


i have question it does not involve past paper though....

1. Construct ionic half equation for:
a) PbO2(s) being reduced to PbSO4(s) in presence of of H2SO4(aq)
b) PbSO4(s) being reduced to Pb(s) in the presence of water.
c) Mow write the balanced equation for the reaction between PbO2 and lead in the presence of dilute sulfuric acid.

please someone EXPLAIN me the steps involved in getting the answer right...

THANK YOU!
 
Messages
438
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53
i am re-posting this question:

Assalamwa'laikum Warahmatullahi Wa Baraqaatuhu...

I AM GIVING CHEM P21 THIS COMING 21st
I am giving AS levels...

i have question it does not involve past paper though....

1. Construct ionic half equation for:
a) PbO2(s) being reduced to PbSO4(s) in presence of of H2SO4(aq)
b) PbSO4(s) being reduced to Pb(s) in the presence of water.
c) Mow write the balanced equation for the reaction between PbO2 and lead in the presence of dilute sulfuric acid.

please someone EXPLAIN me the steps involved in getting the answer right...

THANK YOU!

hey.. umm they are all the same equations. Where did you find this question? and is it half equations that you're confused about?
 
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  1. do have to know the trends of the periodic table?
  2. what do we actually study for chem p5?
  3. if i solve pp is it enough??
 

Jaf

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i am re-posting this question:
a) PbO2(s) being reduced to PbSO4(s) in presence of of H2SO4(aq)
I'm getting:
PbO2 + 4H^(+) + SO4^(2-) + 2e- ------> PbSO4 + 2H2O

This is a perfectly balanced half equation.
But the problem with this equation is that it doesn't make sense. Sulfuric acid is a dibasic acid. This means one mole of H2SO4 will give 2 moles of H+ and one moles of sulfate ions. But here, we have 4 moles of H+ and one moles of sulfate ions. Is such a reaction possible? I don't know.
 
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WHERE THE IS CHEM PAPER 4 THREAD ????? PAPER 4 CARRIES 38 % WEIGHTING MORE THAN ANY OTHER COMPONENT IN CHEMISTRY AND ALL PPL CARE ABOUT IS PAPER 5 AND PAPER 2. PAPER 5 CARRIES ONLY 23% WEIGHTING. IF ANY OF U KNOW WHETHER THERE IS ANY CHEM P4 THREAD PLEASE REPLY .
tnx :)(y)
 
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I'm getting:
PbO2 + 4H^(+) + SO4^(2-) + 2e- ------> PbSO4 + 2H2O

This is a perfectly balanced half equation.
But the problem with this equation is that it doesn't make sense. Sulfuric acid is a dibasic acid. This means one mole of H2SO4 will give 2 moles of H+ and one moles of sulfate ions. But here, we have 4 moles of H+ and one moles of sulfate ions. Is such a reaction possible? I don't know.

Here: Take half equation from this
2 PbO2 + 2 H2SO4 = 2 H2O + O2 + 2PbSO4
 
Messages
438
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106
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53
WHERE THE IS CHEM PAPER 4 THREAD ????? PAPER 4 CARRIES 38 % WEIGHTING MORE THAN ANY OTHER COMPONENT IN CHEMISTRY AND ALL PPL CARE ABOUT IS PAPER 5 AND PAPER 2. PAPER 5 CARRIES ONLY 23% WEIGHTING. IF ANY OF U KNOW WHETHER THERE IS ANY CHEM P4 THREAD PLEASE REPLY .
tnx :)(y)
dude chill, okay? and if you wanna discuss chem p4, do it here.
 
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