oct/nov 02I think
Warrior66 gave the ryt answers buy still can u confirm it?? and yeah which paper is this?
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oct/nov 02I think
Warrior66 gave the ryt answers buy still can u confirm it?? and yeah which paper is this?
thankyou so much!!1. A and B and C
2. C and E (I thought this one was E only though)
3. E
4. C
5. C and D
6. E
Here's the marking scheme
Here are all the Important Chemistry Definitions for AS
i compiled them for quick revision because i always forget the statements of the laws and the definitions even though i have the concept.... so if anyone else has the same problem u can take help from this....
Please Pray for all of us appearing in the CIE this year.... if u pray for others the Angels pray for you Best of Luck =)
coolHere is a checklist of all [i hope ] the organic reactions of AS
if any reactions are missing please tell me too I have a series of mnemonics to learn them too but its kind of a long story if u still want them then inbox me
Best of Luck
thanks ^_^cool
welcomethanks ^_^
ive got my notes mixed sorry :$ they dont only aldehydes change color from orange to greenJazak'Allahum Khairan!!
btw in q 26..you said that ketones can be oxidised by acidified dichromate? I don't think that's right, is it?
.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_22.pdf
Q3 a... please help.. y wud we react NaBr with H2SO4??
it's okay..no prob!ive got my notes mixed sorry :$ they dont only aldehydes change color from orange to green
sulfuric acid is not present in the first stage Im soooooo confused so NaBr is supposed to react with water.
Now step by step explanation the only inorganic reactants NaBr and H2O and H2SO4. now neither Na compounds nor acids under go hydrolyses so for first stage the only reaction possible will be one given below
thenmove on to step 2 the HBr formed will react with the alcohol to form 1 bromobutane sulphuric acid i think catalysis the reaction
reactions
step1 NaBr(aq) +H2SO4(l)=NaHSO4(aq) + HBr(aq)
step2 HBr(aq) +CH3CH2CH2CH2OH =CH3CH2CH2CH2BR + H2O
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