- Messages
- 70
- Reaction score
- 117
- Points
- 18
1- BF3 =
Each F has 7 outer electrons
Each B has 3 outer electrons
So, B forms 3 bonds and hence has 6 electrons (incomplete octet!)
CH3-
Each C has 4 outer electrons
Each H has one outer electron
CH3 has an overall negative charge.
So, C forms 3 bonds and will have 6 electrons.
One electron is left but there is a negative charge so it is gaining an electron. [Well that's what my teacher told me back when I asked him!]
14- 4Al + Ba(NO3)2 -> 2(Al2O3) + Ba + N2
1 mol : 1 mol
0.783/(137+62(2)) = 0.003 mol
1 mol occupies 24dm3
0.003 mol will occupy 0.072dm3
Hence,B
I understood the first question. But I dont really get how you got 137 and 62 for the second question. I understand you took mass/molar mass. Which substance's moles are you tryna find?