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Chemistry: Post your doubts here!

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1- BF3 =
Each F has 7 outer electrons
Each B has 3 outer electrons
So, B forms 3 bonds and hence has 6 electrons (incomplete octet!)

CH3-
Each C has 4 outer electrons
Each H has one outer electron
CH3 has an overall negative charge.

So, C forms 3 bonds and will have 6 electrons.
One electron is left but there is a negative charge so it is gaining an electron. [Well that's what my teacher told me back when I asked him!]

14- 4Al + Ba(NO3)2 -> 2(Al2O3) + Ba + N2

1 mol : 1 mol
0.783/(137+62(2)) = 0.003 mol

1 mol occupies 24dm3
0.003 mol will occupy 0.072dm3
Hence,B


I understood the first question. But I dont really get how you got 137 and 62 for the second question. I understand you took mass/molar mass. Which substance's moles are you tryna find?
 
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I understood the first question. But I dont really get how you got 137 and 62 for the second question. I understand you took mass/molar mass. Which substance's moles are you tryna find?

I need the mols of Ba(NO3)2 to deduce how many mols of N2 will be produced.

I didn't have a periodic table but I remember Ba and NO3 values having used them ample times so I simply plugged 137 and 62x2. You could also do 137+2(14+16+16+16) and it'd give you the same thing. (137+62+62 is the Mr of Ba(NO3)2)

Did you get it?
 
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I need the mols of Ba(NO3)2 to deduce how many mols of N2 will be produced.

I didn't have a periodic table but I remember Ba and NO3 values having used them ample times so I simply plugged 173 and 62x2. You could also do 173+2(14+16+16+16) and it'd give you the same thing. (137+62+62 is the Mr of Ba(NO3)2)

Did you get it?
I think you're mixing up 173 and 137 lol.
My Periodic Table shows that the Mr of Ba is 39.o_O
 
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s12_qp12
4, 6,

I've got a lot more but sadly all of them are from Inorganic:( Will have to ask my lousy teacher lol.


Oh jeez. Contradiction in 4. I'll text my teacher and ask what the method was.

6- P = nRT/V
=> ((0.96/32)(8.31)(30+273))/7000 * 10^-6
=10791.1 Pa
Hence, C

I do know inorganic.
Just haven't done organic.
 
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Oh jeez. Contradiction in 4. I'll text my teacher and ask what the method was.

6- P = nRT/V
=> ((0.96/32)(8.31)(30+273))/7000 * 10^-6
=10791.1 Pa
Hence, C

I do know inorganic.
Just haven't done organic.
Thanks man! Appreciate it.
 
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Thanks man! Appreciate it.


For the first question,

we know CH3- is complete

So, CH3+ has to be incomplete as it's losing 2 electrons. It didn't make sense when I first did it because I thought it was CH3- that was listed.
 
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For the first question,

we know CH3- is complete

So, CH3+ has to be incomplete as it's losing 2 electrons. It didn't make sense when I first did it because I thought it was CH3- that was listed.

2 electrons? What is actually losing the electrons, the C or the H?
 
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how GT is calculated for as level.in the GT it is wriiten that total marks for as level is 130 for chemistry but actually it is 140.plz explain
 
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