u serious bro :/Which compounds may result from mixing ethane and chlorine in the presence of sunlight?
1 CH3CH2Cl
2 CH3CH2CH2CH3
3 CH3CHClCHClCH3
Can someone explain this to me?
1 cause rest hve more then two Cs
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u serious bro :/Which compounds may result from mixing ethane and chlorine in the presence of sunlight?
1 CH3CH2Cl
2 CH3CH2CH2CH3
3 CH3CHClCHClCH3
Can someone explain this to me?
Very serious because the answer is ALL of them...u serious bro :/
1 cause rest hve more then two Cs
tell me the year or send the linkE
Very serious because the answer is ALL of them...
http://papers.xtremepapers.com/CIE/...d AS Level/Chemistry (9701)/9701_w04_qp_1.pdf its question 37tell me the year or send the link
yeah yeah yeah i get it
yeah yeah yeah i get it
1 u know is right
2) when two ethane radicals combine
3) when combination of ethane radical is chlorinated
I'm sorry, but I still don't understand q.6, q.29 why is c not acidic(there is co2h bonded to it).6. Use pV=nRT.
8. Volume is proportional to temperature at constant pressure. You can tell from pV=nRT.
27. Unreactive towards mild oxidising agents = tertiary alcohol. We can get only D from a tertiary alcohol.
29. B and C are not acidic; A is not chiral. That leaves D.
30. The acid used to make this ester is hexanoic acid. Only C shows a hexanoate.
38. Step 1 will give us the product so we won't need steps 2 and 3.
21. Any C=C bond breaks and is replaced with a C=O bond.
29. Draw propanone first, then break the double bond and add an H to the O and a -CN bond. The remove the CN and put CO2H in its place.
30. (30+30)-18(water).
39. Compounds 1 and 2 are formed by the reaction of C3H7 radicals. Compound 3 is formed by the reaction of a C4H9 radical with a C2H5 radical. These last can't be made if only propanone is used.
i think i answered ur queries
http://papers.xtremepapers.com/CIE/...d AS Level/Chemistry (9701)/9701_w05_qp_1.pdf here you gocan u plz attach the link with it
Okay , in A ethanol with sulphuric acid is a hydrolysis reaction , so ethanol loses a water molecule and nothing happens to sulfuric because I think it acts as a catalyst , thus nothing gains or losses oxygen. In C it's also an example of the hydrolysis of an ester , therefore the ester splits into it's acid and alcohol and again nothing gains or loses anything , the hydroxyl group returns to the alcohol from the water and the carboxylic acid gains it's hydrogen back . in D there is no reaction because a ketone doesn't react with fehlings or tollents reagent. However in B tollents reagent is made of silver nitrate dissolved in ammonia right? , so the silver ions will oxidise the aldehyde into a carboxylic acid(oxidation) while they themselves are reduced to silver atoms after gain electrons(reduction) that's why a silver mirror appears on the inside of the tube . I hope I made senseI think the answer is B , am I right?
5 b .. whenever a state change occurs from liquid to gas.. the bonds are broken.. and hydrogen bonding is only present where H is joined with N, O or F.
6 A .. because of Hydrogen Bonding.. The IMF are high.. while to consider a gas to be an ideal gas the inter molecular forces need to be zero.
11 A .. because the Acid will react with OH- to decrease the concentration of OH- ions which will shift equilibrium to right hand side and more product forms...
33 D .. 2 Is wrong because Triple bond is in products and non-reversible reaction so that won't affect how the reactants react.. and N=N bond is present in N2H4 not triple bond.
40 B 1 is correct.. 2 is correct as 2 OH groups are present (OH) and -OH in COOH .. H bonded with O is hydrogen bonding, 3 is wrong since it will form a ketone from secondary alcohol.
I'd suggest that you revise the chapter on bonding from the book or ask your teacher to give you revision on the topic.. since your concepts on Hydrogen bonding seem to be a little weak
then why didn't they tell us to refer to the data booklet? the answer B is phosphorous? But how it's p orbital has 1 electron so it lost two electrons but they're asking for the electron configuration of it's second ionisation energy?Q3-- they did not ask to see the data booklet but it will be a lot easier if u just go through it , A is not correct bcoz it is Mg and its second ionisation energy is not high thn sodium and aluminium, C is not correct because its is silicon and its 2nd ionisation energy is not higher thn Al and P, its not D bcoz its S and evn its 2nd ionisation energy is not higher thn either of their neighbours, so its B
No , a pi bond is the "SIDEWAYS" overlap of two pi orbitals get itmore doubts plz :$
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w06_qp_1.pdf
Q5 for the pi bond isnt it overlapping of two p orbitals, Q11 how to do such ques, Q21, Q39 what are the H2SO4 reactions ??
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_qp_1.pdf
Q9, Q19, Q28
thanks in advance
more doubts plz :$
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w06_qp_1.pdf
Q5 for the pi bond isnt it overlapping of two p orbitals, Q11 how to do such ques, Q21, Q39 what are the H2SO4 reactions ??
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w07_qp_1.pdf
Q9, Q19, Q28
thanks in advance
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