- Reaction score
cud anyone post here sum link fr lectures on carbonyl componds???? plzzzzzz =(
karishma92 said:1 You are provided with the following.
FB 1, 3.00 mol dm–3 hydrochloric acid, HCl
Three tubes containing different mixtures of sodium carbonate, Na2CO3, and sodium
hydrogencarbonate, NaHCO3, each with a total mass of 5.00 g of mixture.
tube labelled mass of Na2CO3 / g mass of NaHCO3 / g % by mass of Na2CO3
FB 2 1.00 4.00 20.0
FB 3 2.50 2.50 50.0
FB 4 4.00 1.00 80.0
You are to determine the temperature change, ΔT, when the contents of each of the tubes FB 2,
FB 3 and FB 4 react with an excess of hydrochloric acid, FB 1.
(a) (i) Calculate the volume of 3.00 mol dm–3 hydrochloric acid required to react with 5.00 g
of sodium carbonate, Na2CO3. Show your working.
Na2CO3(s) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g)
[Mr: Na2CO3, 106.0]
(ii) Calculate the volume of 3.00 mol dm–3 hydrochloric acid required to react with 5.00 g
of sodium hydrogencarbonate, NaHCO3. Show your working.
NaHCO3(s) + HCl(aq) → NaCl(aq) + H2O(l) + CO2(g)
[Mr: NaHCO3, 84.0]
Assalamoalaikum!!hassam said:WHY IS E(cell) = E(right)-E(left)???
see QUESTION 1 http://www.xtremepapers.com/CIE/Interna ... 3_qp_4.pdf
if we use E(CELL)=E(+ve)-E(-VE ELECTRODE) correct ans will not cum .....!!!!
u must see which is more positive E value. For this case the Chromate is more +ve...it shud be written the same way..that is no inverse. The Cl- equation should be reverse as it less +ve!ching293 said:Nov 2007 paper4 question 3, CIE
since Cl2 is more +ve, isnt it suppose to undergo reduction? why is the equation the other way round from what i did