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in s10 qp13 question 30 what r the three alkenes that btan2 ol can produce on dehydration i know its's but1-ene and but2-ene what is the third one?
It's a cis-trans isomer.
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in s10 qp13 question 30 what r the three alkenes that btan2 ol can produce on dehydration i know its's but1-ene and but2-ene what is the third one?
2 moles of one compound is broken down. So divide the energy by 2. And then divide what you get by the number of bonds in the molecule.
No, forget about the bonds broken - bonds formed; you can't do it that way. Only ONE compound is made, so all the bonds made are its own, and all the energy of the reaction goes to it and it alone. There are 2 moles of it, so the energy it used to make 2 compounds. To find the energy needed to make 1 mole, divide the energy needed to make 2 moles by 2. (It's given in the question). Now you have the energy needed to make 1 compound. You need to get the energy needed to break the bonds in that 1 compound. The number of bonds in the compound is 3, so you divide the energy by 3.cud u please quote values of bonds broken and formed...
cud u please quote values of bonds broken and formed...
What you have to do is draw ICE charts for all the equations (A, B, C and D). Then see if the sum of equilibrium moles is 2+x/2.Yet again im posting please do help
" Question number 7 please help
http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s12_qp_12.pdf
And question number 11 and 23
http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s11_qp_12.pdf "
I wrote Na for 30, but the answer is CH3COOH. I have no idea why, as that would give an ester, and that has two O atoms.23 C because only Pentan-3-ol has a chiral carbon. Drawing the displayed formula for such type of questions REALLY helps
30 Na will react with an alcohol to give R-O Na , the number of oxygens remains the same. Elimination will occur with Al2O3, with option B esterification will occur with the acid which increases the number of oxygen atoms and in option C OH group will be replaced by HBr. So D is the answer
Yet again im posting please do help
" Question number 7 please help
http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s12_qp_12.pdf
And question number 11 and 23
http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s11_qp_12.pdf "
Check the mark scheme again. Pretty sure it's Na.I wrote Na for 30, but the answer is CH3COOH. I have no idea why, as that would give an ester, and that has two O atoms.
Check the mark scheme again. Pretty sure it's Na.
24. Because of the rings, the compound can't be planar. Because of the rings, there can exist no cis-trains isomers.
What you have to do is draw ICE charts for all the equations (A, B, C and D). Then see if the sum of equilibrium moles is 2+x/2.
Here's the ICE chart for D:
24. Because of the rings, the compound can't be planar. Because of the rings, there can exist no cis-trains isomers.
8. Pressure depends on the mole ratio, so you'll need to be calculating the moles here. Mass of H2=2 g, molecular mass=2, so n=1. Calculate the total moles in A, B, C and D. C's the answer, if I'm not mistaken.
11. Draw an ICE (initial moles, change in moles, equilibrium moles) chart.
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