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Chemistry: Post your doubts here!

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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w08_qp_4.pdf
Please help me with qn no. 7(d) - both parts. Looks simple but I can't figure it out.
daredevil or anyone else
Thanks
see there are total 7 monomers that make up this polypeptide do if ' O ' is an amino acid and ' - ' is a peptide bond:

O-O-O-O-O-O-O

soo there are six peptide bonds between these amino acids

ii) when 1 peptide bond is formed H2O is released right? so if there are 6 peptide bonds formed then it means that when these monomers will combine, 6H2O molecules will be released. what u have to do here is to add all the Mr of the monomers (remember to multiply the Mr of one monomer with the no of moles of this monomer shown in the eq) when added all the Mr ... u will subtract the Mr of 6 H2O molecules from this.
 
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Oohh i get ur point now...

see they have given us the REDUCTION potential as -1.23 but in this cell O2 is being oxidised so it will be -1.23 instead....
so as 1.23 is larger it will be

1.23-(-0.83) instead :)) got it?
I just can't digest it!
Look in the data booklet it is given O2+4Hplus +4electron=2H2O and it's electrode potential value is +1.23v.now as the question says production of O2 at anode,I will invert the eq and write and it's Eo will become -1.23v right,now cathode Eo is -0.83v.E0 cell should be then -0.83-(-1.23).
I don't know what's wrong with me but plz clear the confusion!thanks alot
 
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see there are total 7 monomers that make up this polypeptide do if ' O ' is an amino acid and ' - ' is a peptide bond:

O-O-O-O-O-O-O

soo there are six peptide bonds between these amino acids

ii) when 1 peptide bond is formed H2O is released right? so if there are 6 peptide bonds formed then it means that when these monomers will combine, 6H2O molecules will be released. what u have to do here is to add all the Mr of the monomers (remember to multiply the Mr of one monomer with the no of moles of this monomer shown in the eq) when added all the Mr ... u will subtract the Mr of 6 H2O molecules from this.
Thank you for the great explanation :)
 
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I just can't digest it!
Look in the data booklet it is given O2+4Hplus +4electron=2H2O and it's electrode potential value is +1.23v.now as the question says production of O2 at anode,I will invert the eq and write and it's Eo will become -1.23v right,now cathode Eo is -0.83v.E0 cell should be then -0.83-(-1.23).
I don't know what's wrong with me but plz clear the confusion!thanks alot
okay now i'm confused O_O :p

Rutzaba A star syed1995
u guys ... any thots? :`)
 
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Why won't SO2 wont show up?
How do you test for SO2 gas? Why would it show up if you're never taught how to test for it -_-

Ok looks like I was mistaken. I just confirmed the CIE amendment to the syllabus for P3.

It was the Pb2+ ion that they've removed not SO2. So, K2Cr2O7 will very much be on the reagents bench and you'll have to test for it by soaking the white strips of filter paper. If it turns from orange to green, voila.
 
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yeah... at least i think it will be fine.
bcz seriously how wud we know if the examiner will write them on the left or the right side. i wudve written it the more standard way : on the right side.

In exam you're supposed to always electrons in terms of addition, not subtraction, even though examiners will often ask you in terms of electrons subtracted.

X + e -> X
never
X - e -> X
 
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In exam you're supposed to always electrons in terms of addition, not subtraction, even though examiners will often ask you in terms of electrons subtracted.

X + e -> X
never
X - e -> X

If what I understand is correct, there is no difference on writing an electron as being added (onto one side of the equation) or subtracted (from the other side of the equation), so any way will be correct in the exam.
 
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Does anyone here have any diagram of electrophoresis? I mean an easy one because Marking schemes shows 3D diagrams. Thank You Suchal Riaz AbbbbY Namehere

This is what I make.

10330375_10152190871883621_8502589674136498735_n.jpg
 
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In exam you're supposed to always electrons in terms of addition, not subtraction, even though examiners will often ask you in terms of electrons subtracted.

X + e -> X
never
X - e -> X
Can u plz solve the electrode potential posted above,there Is a confusion in it.thanks
Bro still waiting for the p5.
 
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