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Chemistry: Post your doubts here!

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Well it seems, someoene already answered...:)
The Chill Master : you gotta check my reasoning..bcos in question 8 i think the functional group is Ketone and Aldehyde and not alcohol..Bcos according to my understanding if its alcohol the valency of carbon is not filled...draw the displayed formula and see if i make sense

http://postimg.org/image/8jdjxeqi1/
I know it HAS to be Aldehyde :) the answer for that is A!
17 is A Bravo THNX

for question 25 1 AND 3 is not an option remember?
 
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can somebody solve thissView attachment 51422


H2O CO H2 CO2
initial no. of moles: 1 1 0 0
n at equilibrium : 1-x 1-x x x

* x = no. of moles of H2O and CO reacted
* whatever the position of equilibrium, there are 2 moles of gas present.

so, no. of H2 formed = 33.3/100 * 2 = 0.666

n(H2) = n(CO2) = 0.666
n(H2O) = n(CO) = 1 - 0.666 = 0.334

Therefore, Kc = (0.666^2)/(0.334^2)
= 3.97608 = 3.98

is the answer correct?
 
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if that is the case then carbonyl compounds should also be soluble and so should be any ester! :|
Not really, remember that organic molecules also have a hydrophobic segment. Recall why alcohols become less soluble as the chain increases. H bonding needs to be significant enough to allow a molecule to dissolve in water, it doesn't mean that a substance will definitely dissolve just because it has H bonding,
 
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yes. I didn't get why u multiplied the moles of H2 by 2?
H2O CO H2 CO2
initial no. of moles: 1 1 0 0
n at equilibrium : 1-x 1-x x x

* x = no. of moles of H2O and CO reacted
* whatever the position of equilibrium, there are 2 moles of gas present.

so, no. of H2 formed = 33.3/100 * 2 = 0.666

n(H2) = n(CO2) = 0.666
n(H2O) = n(CO) = 1 - 0.666 = 0.334

Therefore, Kc = (0.666^2)/(0.334^2)
= 3.97608 = 3.98

is the answer correct?
 
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Well it seems, someoene already answered...:)
The Chill Master : you gotta check my reasoning..bcos in question 8 i think the functional group is Ketone and Aldehyde and not alcohol..Bcos according to my understanding if its alcohol the valency of carbon is not filled...draw the displayed formula and see if i make sense

http://postimg.org/image/8jdjxeqi1/
but an aldehydes means carbon aTom attached directly to functional group and and an h .Though I am not sure
 
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but an aldehydes means carbon aTom attached directly to functional group and and an h .Though I am not sure
yes ...ALDEHYDE
3.jpg
:)
 
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What is the number of isomers of C2H2Cl2 including cis-trans isomers?
A= 2 B= 3 C =4 D= 5 how is the answer B can anyone draw the structures and explain? PLZ?
 
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Well it seems, someoene already answered...:)
The Chill Master : you gotta check my reasoning..bcos in question 8 i think the functional group is Ketone and Aldehyde and not alcohol..Bcos according to my understanding if its alcohol the valency of carbon is not filled...draw the displayed formula and see if i make sense

http://postimg.org/image/8jdjxeqi1/
How did you got 17?o_O
Explanation please
 
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