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gimme a sec..i ll ask my frnds which paper was it..i didn't do that questio any where.Paper?
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gimme a sec..i ll ask my frnds which paper was it..i didn't do that questio any where.Paper?
Ahan!!gimme a sec..i ll ask my frnds which paper was it..i didn't do that questio any where.
Konsa question? xD
told u question 5 ka shuru wala question.Konsa question? xD
Ahhhh... IDK sorry.told u question 5 ka shuru wala question.
no probAhhhh... IDK sorry.
so you should know that only aldehydes react with Fehling's and Tollen's reagent. what happens it that the aldehyde is oxidized to carboxylic acid in both cases. In case of Tollen's reagent, the Ag+ ions act as a mild oxidizing agent and oxidize the aldehyde, and reduce themselves to Ag atoms, which form the silver mirror. so if they say what will be the product when CH3CH2CHO reacts with tollen's reagent, it'll be CH3CH2COOH. same goes for fehling's reagent. the Cu2+ ions act as a mild oxidizing agent and oxidize the aldehyde to a carboxylic acid, and reduce themselves to Cu+ ions, giving the orange color as a precipitate of copper (I) oxide forms.Ok so i know the fehling's and tollens tests and what results you get and all
but i need what the actual reaction takes place
like sometimes it asks you to write the product that is formed with the reaction with fehlings and tollens
So can someone give me a example please and state what the product would be?
Yes. H2 will reduce ketone and aldehyde, not sure why the ms says otherwise.thnkss.. but i was actually asking whether H2 with platinium catalyst reduce the aldehyde or not?
i know NaBH4 will do it..
Ok so i know the fehling's and tollens tests and what results you get and all
but i need what the actual reaction takes place
like sometimes it asks you to write the product that is formed with the reaction with fehlings and tollens
So can someone give me a example please and state what the product would be?
It is +1 before and after reaction.http://www.academia.edu/11211755/9701_w02_qp_1
Q36. How Oxi.no of H doesnt change?
I dont get. Sorry. How?It is +1 before and after reaction.
so you should know that only aldehydes react with Fehling's and Tollen's reagent. what happens it that the aldehyde is oxidized to carboxylic acid in both cases. In case of Tollen's reagent, the Ag+ ions act as a mild oxidizing agent and oxidize the aldehyde, and reduce themselves to Ag atoms, which form the silver mirror. so if they say what will be the product when CH3CH2CHO reacts with tollen's reagent, it'll be CH3CH2COOH. same goes for fehling's reagent. the Cu2+ ions act as a mild oxidizing agent and oxidize the aldehyde to a carboxylic acid, and reduce themselves to Cu+ ions, giving the orange color as a precipitate of copper (I) oxide forms.
please do correct me if I've got anything wrong
Thanks to both of you!Yes. H2 will reduce ketone and aldehyde, not sure why the ms says otherwise.
You'll get the carboxylate salt RCOO- with Cu2O (red brown ppt) for Fehlings.
And carboxylate salt with Ag ( silver mirror) with Tollens.
NH3I dont get. Sorry. How?
Isnt it +3 and +4?
This is dehydration of alcohol. OH group must be removed, along with H from a carbon next-doorAfter Y, when concentrated. H2SO4, is added why is the OH group removed? Why not the COOH? :s because the formula that I came up with is: CH2=CHCH(OH)CO2H
We measure oxidation states in terms of each atom.I dont get. Sorry. How?
Isnt it +3 and +4?
You don't have to know any other product, except H2O sometimes...wht are the products formed when a i) Ketone ii) Carboxylic Acid
reacts with LiAlH4 in dry ether
One is the alcohol ofc as its a reducing agent
but do i need to knw other products?
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