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See since this is in three dimensions and not two when you rotate G the COOH which is coming out of the plane of paper would now go into the plane of paper and NH2 would come out,however rotating J from the right side the OH bond will go in and H will come out which is what we want.
Thanks! Okay so I get why it's J but then this small doubtSee since this is in three dimensions and not two when you rotate G the COOH which is coming out of the plane of paper would now go into the plane of paper and NH2 would come out,however rotating J from the right side the OH bond will go in and H will come out which is what we want.
If the temperature of the solution which you're experimenting with rises, then the experiment is exomethermic otherwise if it drops then it'll be endothermic.
thank you so much
Thanks! Okay so I get why it's J but then this small doubt
So rotating G would look like that so can you explain how when "you rotate G the COOH which is coming out of the plane of paper would now go into the plane of paper"
Because according to the diagram on rotation it would be along the same plane of the paper...
See basically in your diagram what you're doing is shifting the groups in two dimension however in reality it would be the three-dimensional model the whole bond along with the group would rotate.So on rotation of 180 degree the bonds that go in come outwards and those that come out intially go inwards, however the ones along the plane remain intact.I can imagine it would be hard to visualize so basically let's say this diagramThanks! Okay so I get why it's J but then this small doubt
So rotating G would look like that so can you explain how when "you rotate G the COOH which is coming out of the plane of paper would now go into the plane of paper"
Because according to the diagram on rotation it would be along the same plane of the paper...
R2 would be COOH, NH2 would be R1 and R3 is H.So if you visualize rotating it you should get J.
View attachment 59118
View attachment 59119
Can anyone please help me out with the apparatus of the above question?
Is is 2012 paper 52 summer session
Marking scheme
View attachment 59120
http://papers.gceguide.com/A Levels/Chemistry (9701)/9701_w15_qp_42.pdf
pls explain qs 3(b)(ii) and (c)
ms:http://papers.gceguide.com/A Levels/Chemistry (9701)/9701_w15_ms_42.pdf
TIA
Ligands must be able to donate a pair of electrons since they form a dative covalent with the central atom of whatever they are bonding to... which can only be done by NO3- (Nitrogen lone pair) and the other long molecule (It has Nitrogen with lone pair again). In NH4+ the lone pair on nitrogen is already donated to the extra Hydrogen and in BF3, B doesnt have any lone pairs either.
c ... what exactly should I explain?
there's something called paper 6 in AL chem? :O
Yess.... 2015 o/n 41
Never <_<wow :O that's ... recent
these examiners ain't leaving anything out are they
which question plz?
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