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which ppr??
yes i've visited that site thankyou but i still need a bit of help with the specific question i mentionedhttp://cieoandalevelnotes.blogspot.in/2015/05/chemistry-level-paper-5-p5-solved-past.html Follow the link in that website ... it has solved chemistry P5 ... might help you out.
You kinda have ... especially Organic chem, group 2,17 and periodic table, and well, the basics about bond angle, shape, orbitals and stuff ... they ask everythingThose whom have given AS before already. Are you guys gonna read AS material again for A 2 session?
There are two types of Cl: Cl35 and Cl37
Thank you so much.You kinda have ... especially Organic chem, group 2,17 and periodic table, and well, the basics about bond angle, shape, orbitals and stuff ... they ask everything
There was this paper 4 ... w13 i guess ... it had soo much of AS in it
In math, even if there's anything from AS, it will be something you need for solving A2 problems. For example, trigonometry graphs and solving basics are needed from AS but I don't think you need to revise AS for that. In one p3 question, we had to apply sequence formula ... but even that formula was given in formula sheet. So just remember that sometimes, you might have to think in the AS way.Thank you so much.
I ll check the paper right away.
And Can you tell we have to revise for Other subjects? Like physics mathematics and biology?
I am not sure what is supposed to be surprising. Is it the plus charge?
Firstly, they told us that benzene is planar and cyclohexane CANNOT be planar.
Step 1 is slowest: So reaction rate depends on concentration of H2O2 and I-, both one mole, so a=1, b=1, c=0 (no dependence on H+)
Step 2 is slowest: reaction rate is dependent on IO- and H+. Now we have the H+ in the rate equation, so we can set c=1, but where is IO-?? How do we take that to account? Why isn't it even in the rate reaction? Because it is an INTERMEDIARY!.
You must always account for intermediaries in slow steps by tracing it back and seeing what produced it.
So our reaction depends on IO-, and IO- is generated by step1, so IO- depends on H2O2 and I-.
So we depend on three things: H2O2, I-, and H+. Each is 1 mole. So a=1, b=1, c=1.
Step 3 is slowest. Same method as above.
Dependent on HOI, H+ and I-.
HOI was made by IO- and H+, so lets replace the sentence above:
IO-, H+, H+, I-
Replace IO- by what produced it: (H2O2 and I-):
H2O2, I-, H+, H+, I-
So you can see there are two moles of H+ being dependent upon, and two moles of I-, so b=2, c=2, and a =1.
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