Chemistry: Post your doubts here!

[innovative_1]

View attachment 63726 View attachment 63727

Someone plz explain these...also plz explain why the other options are wrong

 

[abbas haider]

View attachment 63726 View attachment 63727

Someone plz explain these...also plz explain why the other options are wrong

4 B .... in Al2Cl6 1 Al atom has 4 bonds thus 8 electrons .....In CH3+ = 4 electron of carbon naturally 3 electron given by H -1 due to + chage so 4+3-1 = 6 ....In Cl2O ..(just like H20) oxygen in g6 + 2 bonded electrons = 8 ....In H2ClC. C radical (1 electron un paired) means carbon is bonded to 3 atoms and C-Cl means Cl has 8 ....

 

[innovative_1]

View attachment 63726 View attachment 63727

Someone plz explain these...also plz explain why the other options are wrong

 

[A*****]

4 B .... in Al2Cl6 1 Al atom has 4 bonds thus 8 electrons .....In CH3+ = 4 electron of carbon naturally 3 electron given by H -1 due to + chage so 4+3-1 = 6 ....In Cl2O ..(just like H20) oxygen in g6 + 2 bonded electrons = 8 ....In H2ClC. C radical (1 electron un paired) means carbon is bonded to 3 atoms and C-Cl means Cl has 8 ....

Thankssss

 

[Kanekii]

For 32, O has 2 unpaired p electrons and for the Cl+, u need to understand that Cl atom has 5 p electrons, 2 paired and 1 unpaired...when Cl+ is formed, the electron removed is from the full p orbital, leaving 2 unpaired p electrons behind
Once u understand this, u can easily work out 2 and 3

Thank youuu so mucchh

 

[A*****]

Plz help me with these

 

[innovative_1]

Plz help me with these

View attachment 63734 View attachment 63735 View attachment 63736

Well for 14 ig it is B? As thermal decomposition is always endothermic while in reaction 2 it is exothermic because the it is the formation of the product so energy released

 

[innovative_1]

Plz help me with these

View attachment 63734 View attachment 63735 View attachment 63736

Well for 33 it is D? I'm not sure tho let take an option 2 which is not possible bcoz it is reversible reaction so it can shift backward so less so4 is formed

 

[innovative_1]

Plz help me with these

View attachment 63734 View attachment 63735 View attachment 63736

24 it's C?

 

[A*****]

Well for 14 ig it is B? As thermal decomposition is always endothermic while in reaction 2 it is exothermic because the it is the formation of the product so energy released

Yes it is B
I'm a bit confused about reaction 2...there will be some bonds breaking as well which is endothermic so how do we know that the overall reaction is exo?

 

[A*****]

Well for 33 it is D? I'm not sure tho let take an option 2 which is not possible bcoz it is reversible reaction so it can shift backward so less so4 is formed

Oh yes tysm

 

[A*****]

24 it's C?

No it's A
How are the bonds supposed to break in this compound?

 

[innovative_1]

Yes it is B
I'm a bit confused about reaction 2...there will be some bonds breaking as well which is endothermic so how do we know that the overall reaction is exo?

For this type of question we consider overall reaction like see only one product is formed from reaction 2 for reaction one 2 formed means bonds r broken

 

[innovative_1]

No it's A
How are the bonds supposed to break in this compound?

Cracking results in formation of alkanes n alkene like suppose it is long chain of ch3ch2ch2ch2ch=ch2 so if u see W alkene is formed when bond broken between ch2 and ch

 

[A*****]

Cracking results in formation of alkanes n alkene like suppose it is long chain of ch3ch2ch2ch2ch=ch2 so if u see W alkene is formed when bond broken between ch2 and ch

But how will Z form?

 

[Kanekii]

But how will Z form?

The question states which of these combinations can form from cracking so we can make multiple combinations for example:
CH3(CH2)5CH=CH2 = CH3(CH2)2CH3 + CH2=CHCH=CH2
which now proves Z is correct.
CH3(CH2)5CH=CH2 = CH3CH=CH2 + CH2=CH2 + CH2=CHCH3
Similarly X and W is proved.
CH3(CH2)5CH=CH2 = CH3CH2CH3 + CH2=C=CH2 +CH2=CH2
Y proved.
Hope it helps ^^

 

[A*****]

The question states which of these combinations can form from cracking so we can make multiple combinations for example:
CH3(CH2)5CH=CH2 = CH3(CH2)2CH3 + CH2=CHCH=CH2
which now proves Z is correct.
CH3(CH2)5CH=CH2 = CH3CH=CH2 + CH2=CH2 + CH2=CHCH3
Similarly X and W is proved.
CH3(CH2)5CH=CH2 = CH3CH2CH3 + CH2=C=CH2 +CH2=CH2
Y proved.
Hope it helps ^^

So we can make anything out of it, right?

 

[Kanekii]

So we can make anything out of it, right?

Yes since this equation 1 which proved Z was from the examiner report and its impossible to form the given compound by only using W,X,Y and Z but the product must contain atleast one of the following

 

[abbas haider]

The question states which of these combinations can form from cracking so we can make multiple combinations for example:
CH3(CH2)5CH=CH2 = CH3(CH2)2CH3 + CH2=CHCH=CH2
which now proves Z is correct.
CH3(CH2)5CH=CH2 = CH3CH=CH2 + CH2=CH2 + CH2=CHCH3
Similarly X and W is proved.
CH3(CH2)5CH=CH2 = CH3CH2CH3 + CH2=C=CH2 +CH2=CH2
Y proved.
Hope it helps ^^

Actually in cracking reactions you can make any alkane or alkene (given that no of carbon atoms and hydrogen atoms are less or equal to the reactant (Alkane Or Alkene )

Btw I thaught only cracking of alkanes is possible.... anyidea if cracking of Alkynes or Arenes possible or not???

 

[Kanekii]

Need Help with these :3