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Chemistry: Post your doubts here!

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View attachment 63722 View attachment 63723 Need help with this.
For the first one i know its a reaction pathway of SN1 reaction but why can it not be A or D since they don't have graphs like that i guess
For 32, O has 2 unpaired p electrons and for the Cl+, u need to understand that Cl atom has 5 p electrons, 2 paired and 1 unpaired...when Cl+ is formed, the electron removed is from the full p orbital, leaving 2 unpaired p electrons behind
Once u understand this, u can easily work out 2 and 3
 
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View attachment 63726 View attachment 63727

Someone plz explain these...also plz explain why the other options are wrong

4 B .... in Al2Cl6 1 Al atom has 4 bonds thus 8 electrons .....In CH3+ = 4 electron of carbon naturally 3 electron given by H -1 due to + chage so 4+3-1 = 6 ....In Cl2O ..(just like H20) oxygen in g6 + 2 bonded electrons = 8 ....In H2ClC. C radical (1 electron un paired) means carbon is bonded to 3 atoms and C-Cl means Cl has 8 ....
 
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4 B .... in Al2Cl6 1 Al atom has 4 bonds thus 8 electrons .....In CH3+ = 4 electron of carbon naturally 3 electron given by H -1 due to + chage so 4+3-1 = 6 ....In Cl2O ..(just like H20) oxygen in g6 + 2 bonded electrons = 8 ....In H2ClC. C radical (1 electron un paired) means carbon is bonded to 3 atoms and C-Cl means Cl has 8 ....
Thankssss(y)
 
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For 32, O has 2 unpaired p electrons and for the Cl+, u need to understand that Cl atom has 5 p electrons, 2 paired and 1 unpaired...when Cl+ is formed, the electron removed is from the full p orbital, leaving 2 unpaired p electrons behind
Once u understand this, u can easily work out 2 and 3
Thank youuu so mucchh :D
 
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Well for 14 ig it is B? As thermal decomposition is always endothermic while in reaction 2 it is exothermic because the it is the formation of the product so energy released
Yes it is B
I'm a bit confused about reaction 2...there will be some bonds breaking as well which is endothermic so how do we know that the overall reaction is exo?
 
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Yes it is B
I'm a bit confused about reaction 2...there will be some bonds breaking as well which is endothermic so how do we know that the overall reaction is exo?
For this type of question we consider overall reaction like see only one product is formed from reaction 2 for reaction one 2 formed means bonds r broken
 
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But how will Z form?
The question states which of these combinations can form from cracking so we can make multiple combinations for example:
CH3(CH2)5CH=CH2 = CH3(CH2)2CH3 + CH2=CHCH=CH2
which now proves Z is correct.
CH3(CH2)5CH=CH2 = CH3CH=CH2 + CH2=CH2 + CH2=CHCH3
Similarly X and W is proved.
CH3(CH2)5CH=CH2 = CH3CH2CH3 + CH2=C=CH2 +CH2=CH2
Y proved.
Hope it helps ^^
 
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The question states which of these combinations can form from cracking so we can make multiple combinations for example:
CH3(CH2)5CH=CH2 = CH3(CH2)2CH3 + CH2=CHCH=CH2
which now proves Z is correct.
CH3(CH2)5CH=CH2 = CH3CH=CH2 + CH2=CH2 + CH2=CHCH3
Similarly X and W is proved.
CH3(CH2)5CH=CH2 = CH3CH2CH3 + CH2=C=CH2 +CH2=CH2
Y proved.
Hope it helps ^^
So we can make anything out of it, right?
 
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