• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Chemistry: Post your doubts here!

Messages
665
Reaction score
13,617
Points
503
Is that always the case or CIE prefers this one? What if i connect the voltmeter other way around? The magnitude remains same but the sign changes.
This is always the case. A negative value is never considered becuz that shows that the reaction is not feasible.
Usually the voltmeter is connected with + terminal on the higher electrode potential so just remember larger - smaller for all.

Don't use it for feasibilities. It has a different method. Don't confuse it with E of cell.
 
Messages
84
Reaction score
25
Points
28
This is always the case. A negative value is never considered becuz that shows that the reaction is not feasible.
Usually the voltmeter is connected with + terminal on the higher electrode potential so just remember larger - smaller for all.

Don't use it for feasibilities. It has a different method. Don't confuse it with E of cell.
Well, group IV chlorides are removed from the syllabus, right? I have not done the recent papers but it appears frequently in test papers which were administered before 2016
 
Messages
5
Reaction score
0
Points
1
Iron(III) chloride, FeCl 3, is used to dissolve unwanted copper from printed circuit boards
(PCBs) by the following reaction.
2FeCl 3(aq) + Cu(s) → 2FeCl 2(aq) + CuCl 2(aq)
A solution in which [Fe3+(aq)] was originally equal to 1.50 mol dm–3 was re-used several
times to dissolve copper from the PCBs, and was then titrated as follows.
A 2.50 cm3
sample of the partially-used-up solution was acidifi ed and titrated with
0.0200 mol dm–3 KMnO4.
This oxidised any FeCl 2 in the solution back to FeCl 3.
It was found that 15.0 cm3
How one know that which MnO-4 half equation use

MnO4– + 4H++ 3e– MnO2 + 2H2O +1.67
MnO4– + 8H++ 5e– Mn2+ + 4H2O +1.52
 
Messages
5
Reaction score
0
Points
1
How one know that which MnO-4 half equation use

MnO4– + 4H++ 3e– MnO2 + 2H2O +1.67
MnO4– + 8H++ 5e– Mn2+ + 4H2O +1.52
 
Messages
500
Reaction score
419
Points
73
Messages
17
Reaction score
14
Points
13
How many stereoisomers does piperic acid have? I mean the answer is 4 but i actually drew 8 of them and they are all different in terms of spatial arrangement. I hope you understand the spatial crisis here. I would be grateful if somebody could explain it to me.
 

Attachments

  • imgsrv.png
    imgsrv.png
    2.3 KB · Views: 4
Messages
17
Reaction score
14
Points
13
It just simply does not react with bromine 'No reaction occurs'.
Here the question is basically focusing on where the the bromine will attach what will be the specified position which in this case are 2 & 6 as -OH is electron donating group.
why does br2 not react with the double bond?
 
Messages
17
Reaction score
14
Points
13
Q3)b)
i) Why does Br2 not react with the double bond?
ii)why does ethyol chloride not react with N in the ring ?
 

Attachments

  • November 2017 (v2) QP - Paper 4 CIE Chemistry A-level.pdf
    543.1 KB · Views: 3
Messages
4
Reaction score
3
Points
13
Hey can some one help with the concept of tetrahedral and square planer complex? How to differentiate between the two?
Also this question, how do we know which equation from databooklet to use for Fe3 : 1) Fe3 + 3e- => Fe or 2) Fe3 + e- => Fe2
 

Attachments

  • Screenshot (10).png
    Screenshot (10).png
    117.3 KB · Views: 4
Messages
500
Reaction score
419
Points
73
Hey can some one help with the concept of tetrahedral and square planer complex? How to differentiate between the two?
Also this question, how do we know which equation from databooklet to use for Fe3 : 1) Fe3 + 3e- => Fe or 2) Fe3 + e- => Fe2
For your first question,
you will not have to be able to tell the difference between square planar and tetrahedral just based on the formula. However, if there is a name of a coordination complex with four ligands and cis- or trans- is specified, then you know that the complex must be square planar because all positions on a tetrahedral complex are equivalent. If neither cis- or trans- is specified, the compound may be either square planar or tetrahedral and you will not need to know the difference.

And also it mentions in the syllabus Tetrahedral OR square planar complex I think it is considered the same.
 
Top