• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Chemistry: Post your doubts here!

Messages
35
Reaction score
0
Points
16
Why doesn’t compound A react with Al2O3 or acidified K2Cr2O7? Shouldn’t it get oxidized ?
 

Attachments

  • EF5E2746-AC56-4A6E-BCBD-92D9B253E4E2.png
    EF5E2746-AC56-4A6E-BCBD-92D9B253E4E2.png
    170.9 KB · Views: 6
Messages
35
Reaction score
0
Points
16
How do you draw the repeating unit? I never seem to get these questions right, is there a certain method to use? How do you know what’s on the side chain?
 

Attachments

  • A2A277EE-13EF-4A2F-B09E-72FA87DE6E18.png
    A2A277EE-13EF-4A2F-B09E-72FA87DE6E18.png
    225 KB · Views: 7
Messages
96
Reaction score
53
Points
28
how to deduce the rate determining step

I'm guessing you have the rate equation from previous parts?

The rate equation gives you the molecules involved in the rate determining step (or, if one of the reactants in the rate determining step is a product from another step and doesn't show up in the overall reaction equation, it will show the reactants that formed it) and the powers in the rate equation give the molar ratio in the rate determining step.
(this vid explains it better :
)

Why doesn’t compound A react with Al2O3 or acidified K2Cr2O7? Shouldn’t it get oxidized ?
Which paper is this?

How do you draw the repeating unit? I never seem to get these questions right, is there a certain method to use? How do you know what’s on the side chain?

Look at whats bonded to the two double bonded carbons, one has 2Hs, one has 1H and CO2H
 
Messages
35
Reaction score
0
Points
16
I'm guessing you have the rate equation from previous parts?

The rate equation gives you the molecules involved in the rate determining step (or, if one of the reactants in the rate determining step is a product from another step and doesn't show up in the overall reaction equation, it will show the reactants that formed it) and the powers in the rate equation give the molar ratio in the rate determining step.
(this vid explains it better :
)


Which paper is this?

It’s summer 2013 variant 41

Look at whats bonded to the two double bonded carbons, one has 2Hs, one has 1H and CO2H
 
Messages
35
Reaction score
0
Points
16
Guys how do you solve this buffer solution question?
 

Attachments

  • D3250730-69F7-4BE7-9517-6D510E22AEC2.png
    D3250730-69F7-4BE7-9517-6D510E22AEC2.png
    188.9 KB · Views: 4
Messages
42
Reaction score
4
Points
8
I'm guessing you have the rate equation from previous parts?

The rate equation gives you the molecules involved in the rate determining step (or, if one of the reactants in the rate determining step is a product from another step and doesn't show up in the overall reaction equation, it will show the reactants that formed it) and the powers in the rate equation give the molar ratio in the rate determining step.
(this vid explains it better :
)


Which paper is this?



Look at whats bonded to the two double bonded carbons, one has 2Hs, one has 1H and CO2H


thanks man
 
Messages
35
Reaction score
0
Points
16
I'm guessing you have the rate equation from previous parts?

The rate equation gives you the molecules involved in the rate determining step (or, if one of the reactants in the rate determining step is a product from another step and doesn't show up in the overall reaction equation, it will show the reactants that formed it) and the powers in the rate equation give the molar ratio in the rate determining step.
(this vid explains it better :
)


Which paper is this?



Look at whats bonded to the two double bonded carbons, one has 2Hs, one has 1H and CO2H


But what about this structure ? I got CH2-CH-COOH as the monomer but the marking scheme says CH2=CH-COOH, why is there a double bond?
 

Attachments

  • 0A1743C5-E5D3-42B4-9693-227B70181968.png
    0A1743C5-E5D3-42B4-9693-227B70181968.png
    207.3 KB · Views: 4
Messages
35
Reaction score
0
Points
16
For b iv) how do we know how to form the equation ? Why is it NaSnO3?
 

Attachments

  • 6955481A-22C6-43C2-8380-E1683A024CD3.png
    6955481A-22C6-43C2-8380-E1683A024CD3.png
    161.6 KB · Views: 3
Top