Chemistry: Post your doubts here!

[Bishnu Dev]

Please explain b)

 

[Sheraz ali]

Iron(III) chloride, FeCl 3, is used to dissolve unwanted copper from printed circuit boards
(PCBs) by the following reaction.
2FeCl 3(aq) + Cu(s) → 2FeCl 2(aq) + CuCl 2(aq)
A solution in which [Fe3+(aq)] was originally equal to 1.50 mol dm–3 was re-used several
times to dissolve copper from the PCBs, and was then titrated as follows.
A 2.50 cm3
sample of the partially-used-up solution was acidifi ed and titrated with
0.0200 mol dm–3 KMnO4.
This oxidised any FeCl 2 in the solution back to FeCl 3.
It was found that 15.0 cm3
How one know that which MnO-4 half equation use

MnO4– + 4H++ 3e– MnO2 + 2H2O +1.67
MnO4– + 8H++ 5e– Mn2+ + 4H2O +1.52

 

[Sheraz ali]

How one know that which MnO-4 half equation use

MnO4– + 4H++ 3e– MnO2 + 2H2O +1.67
MnO4– + 8H++ 5e– Mn2+ + 4H2O +1.52

 

[Hamnah Zahoor]

View attachment 64308View attachment 64309
Can anybody help . Nov/17/p42 question 3.
Why has the NH not reacted ?
View attachment 64310
As seen on the marking scheme

It just simply does not react with bromine 'No reaction occurs'.
Here the question is basically focusing on where the the bromine will attach what will be the specified position which in this case are 2 & 6 as -OH is electron donating group.

 

[hamadh]

How many stereoisomers does piperic acid have? I mean the answer is 4 but i actually drew 8 of them and they are all different in terms of spatial arrangement. I hope you understand the spatial crisis here. I would be grateful if somebody could explain it to me.

 

[hamadh]

It just simply does not react with bromine 'No reaction occurs'.
Here the question is basically focusing on where the the bromine will attach what will be the specified position which in this case are 2 & 6 as -OH is electron donating group.

why does br2 not react with the double bond?

 

[hamadh]

Q3)b)
i) Why does Br2 not react with the double bond?
ii)why does ethyol chloride not react with N in the ring ?

 

[Hamnah Zahoor]

why does br2 not react with the double bond?

CCl4 is used as a solvent for electrophillic addition to occur with bromine But as seen in the question the bromine is in aqueous form thus it will not react with the double bond.

 

[hamadh]

View attachment 64313
CCl4 is used as a solvent for electrophillic addition to occur with bromine But as seen in the question the bromine is in aqueous form thus it will not react with the double bond.

Thank you so much!!

 

[Hamnah Zahoor]

Thank you so much!!

You are welcome

 

[Horsey]

Hey can some one help with the concept of tetrahedral and square planer complex? How to differentiate between the two?
Also this question, how do we know which equation from databooklet to use for Fe3 : 1) Fe3 + 3e- => Fe or 2) Fe3 + e- => Fe2

 

[Hamnah Zahoor]

Hey can some one help with the concept of tetrahedral and square planer complex? How to differentiate between the two?
Also this question, how do we know which equation from databooklet to use for Fe3 : 1) Fe3 + 3e- => Fe or 2) Fe3 + e- => Fe2

For your first question,
you will not have to be able to tell the difference between square planar and tetrahedral just based on the formula. However, if there is a name of a coordination complex with four ligands and cis- or trans- is specified, then you know that the complex must be square planar because all positions on a tetrahedral complex are equivalent. If neither cis- or trans- is specified, the compound may be either square planar or tetrahedral and you will not need to know the difference.

And also it mentions in the syllabus Tetrahedral OR square planar complex I think it is considered the same.

 

[Hamnah Zahoor]

 

[Horsey]

View attachment 64327

Thankyou so much Hamnah
Can you tell the name of shape and structure of Ni(CN)2(NH3)2 ?

 

[Hamnah Zahoor]

Thankyou so much Hamnah
Can you tell the name of shape and structure of Ni(CN)2(NH3)2 ?

 

[Horsey]

View attachment 64329

Oh thanks

 

[Ayesha_m8]

help and explain why is it rxn2 :'(

 

[Raheel327]

Hydrogen Iodide dissociates into H2 and I2.
2HI (g) <-----> H2 (g) + I2 (g) (the reaction goes in both directions)
In an experiment, b mol of hydrogen iodide were put into a sealed vessel at pressure p. At equilibrium, x mol of the hydrogen iodide had dissociated. Which expression for Kp is correct?
A. x^2/(b-x)^2 B. x^2×p^2/(b-x)^2 C. x^2×p^2/4b(b-x) D. x^2/4(b-x)^2
The ice table method doesnt work here. The answer is D.
I am getting x^2/(b-2x)^2

 

[A*****]

Hydrogen Iodide dissociates into H2 and I2.
2HI (g) <-----> H2 (g) + I2 (g) (the reaction goes in both directions)
In an experiment, b mol of hydrogen iodide were put into a sealed vessel at pressure p. At equilibrium, x mol of the hydrogen iodide had dissociated. Which expression for Kp is correct?
A. x^2/(b-x)^2 B. x^2×p^2/(b-x)^2 C. x^2×p^2/4b(b-x) D. x^2/4(b-x)^2
The ice table method doesnt work here. The answer is D.
I am getting x^2/(b-2x)^2

x moles of HI have dissociated which will give x/2 moles of H2 and x/2 moles of I2
When u will write the expression, the numerator will be ( x/2)² = x²/4 and the 4 will go in the denominator to form x²/4(b-x)²

 

[Tajrina Promela]

Can anyone solve this, please?