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YESSSS, but how?is option A correct answer?
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YESSSS, but how?is option A correct answer?
For this you will have to learn the ionisation energy graph given in the book and know that in the first period highest ionisation energy is that of noble gases and when we shift to the next the ionisation energy decreases by a great extent. As H+ is invloved the other element is from group 7YESSSS, but how?

For this you will have to learn the ionisation energy graph given in the book and know that in the first period highest ionisation energy is that of noble gases and when we shift to the next the ionisation energy decreases by a great extent. As H+ is invloved the other element is from group 7View attachment 65306
No problemOmg!! Thank you so muchhh!!!
Thank you , that’s what I thought 😂At this temperature water also exist as gas so also add up the volume of water.
Please help!
YESSSS, but how?
is option A correct answer?
X is definitely Si which reacts with chlorine to give SiCl4, a colourless liquid at r.t.p.X, Y and Z are three elements in the third period.
● X reacts with chlorine to give a liquid product.
● Y reacts with chlorine to give a solid product that dissolves in water to give a
solution of pH 7.
● Z reacts with chlorine to give a solid product that dissolves in water to give a solution
of pH 6.
Which elements are good conductors of electricity?
I think you didn't post the complete question. Do upload a SS from the question paper and I'll try to solve it 😁A solution contains both Mg2+(aq) and Sr2+(aq) at the same concentration.
The solution is divided into two equal portions. Aqueous sodium hydroxide is added dropwise to
one portion. Dilute sulfuric acid is added dropwise to the other portion.
Which row is correct?
I mostly use the process of elimination to reach the correct answer for these type of questions.Compound X produces a carboxylic acid when heated under reflux with acidified
potassium dichromate(VI). Compound X does not react with sodium metal.
What could be the identity of compound X?
A propanal
B propanone
C propan-1-ol
D propan-2-ol
answer is propanal but why?
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