If you draw the propene molecule, it will help. so the molecule looks something like this: CH2=CH-CH3. Now we have Br2 which is (i) Br-Br and HBr which is (ii) H-Br. In case (i) the nucleophile will attack. the double bond will break and one extra bond will be available on C1 and one more on C2. a Br ion can attach to each one of these free bonds, thus forming option D. in (ii) H can bond to first free bond or the second. Br will attach to the one left. Through this, the process forms option A and B.Can someone explain why the answer is C ?
Thank you so much!!!!If you draw the propene molecule, it will help. so the molecule looks something like this: CH2=CH-CH3. Now we have Br2 which is (i) Br-Br and HBr which is (ii) H-Br. In case (i) the nucleophile will attack. the double bond will break and one extra bond will be available on C1 and one more on C2. a Br ion can attach to each one of these free bonds, thus forming option D. in (ii) H can bond to first free bond or the second. Br will attach to the one left. Through this, the process forms option A and B.
Option C is impossible because it implies that both the bromine ions went to the first carbon, but that is not possible because if you revisit molecular bonding, a pi bond is basically an unhybridised p orbital from each atom interacting. SO the breaking of a double bond will automatically free up one unhybridised p orbital on either C atom. You just can't have option C. Others are possible, as described above.
Hope this helps
So the graph is characteristics for an ENDO thermic reaction which is deltaH +ve value. For the reverse reaction, energy needs to be supplied to increase the potential energy of products to the energy level of intermediate(which has a greater potential energy). So this also requires an INPUT of energy (i.e, +ve sign). This makes C the right answer.Can anyone pls explain why is the is answer C? Thank you
Al2O3 does react with acid and alkali since it is amphoteric.OK so first you need to know the reactions of the period 3 oxides with water. AL2O3 does not react so optionA b are wrong. Next we react 2NaOH (which is a basic oxide and the product of reaction between oxide and H2O) with corresponding acidic oxide & balance the equations.
NOTE The Q states"neutralised by exactly 1mol....so D is correct as it balances perfectly with 2NaOH.
Hey brother, I don’t think this statement is correct. Gas can be liquified by increasing pressure at constant T. Just look at phase diagram.compressing at constant temp will never liquify any gas... you have to cool the cylinder as well for liquifying... else the cylinder will blast away....
silicon dioxide has a giant molecular structure and consist of only strong covalent bomdWhich solid contains more than one kind of bonding?
B. Silicon dioxide
C. Sodium chloride
The answer is A but I don't understand really why. I know that it has covalent bonds and van der waals forces, but don't silicon dioxide and sodium chloride also have those?
Which element is likely to have an electronegativity similar to that of aluminium?
I have no clue as to how to figure this one out
Suggest an explanation for the existence of IF7 and for the non-existence of ClF7? The answer says because I is a bigger atom than Cl but I need a more thorough explanation as I didn't understand anything from that answer.
The gas is behaving ideally, use PV=nRT before and after compression and make n the subject. You'll see that for both equations n is constant.in an experiment a sample of a pure gas is put into a gas syringe at a temperature of 300K and pressure of 16 kpa. the gas is compressed until the volume occupied by the gas is halved.
after the compression, the temperature of the gas in syringe is 375 and the pressure is 40 kpa.
is the gas is ideal