- Messages
- 37
- Reaction score
- 15
- Points
- 18
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Heyy ... I had to ask for help because I was bamboozled by the fact that 1 is not correct. Here's the deal. 1 is wrong because the equilibrium pressure will only be reached once the external pressure (atmospheric pressure) is equal to the internal pressure .Work will be done by the expanding gas until the pressures inside and out even each other . This is an application of some Isobaric Processes Theory I suggest you look that up.View attachment 65257Can anyone explain the first point , and why’s its wrong and the third one
I’m mind blown right now😂😂 that’s such an important pointer right thereHeyy ... I had to ask for help because I was bamboozled by the fact that 1 is not correct. Here's the deal. 1 is wrong because the equilibrium pressure will only be reached once the external pressure (atmospheric pressure) is equal to the internal pressure .Work will be done by the expanding gas until the pressures inside and out even each other . This is an application of some Isobaric Processes Theory I suggest you look that up.
Number 3 can be explained in two ways . The English there was a bit tricky for me 😂😂😂 . (1)Well the expanding gas(from dissociation products) pushes back on the plunger and hence that is the increase in the volume there
(2) There's increase in moles of gases and since moles of gases directly proportional to the volume from PV=nRT thus theres a higher volume than there would be if no dissociation occurred
check your conversions of pressure and volume , because I got 130.8 as the answer which I assume is for XenonCan anyone help solve this, I used Mr=MRT/PV but I couldn't get a proper value.
When an evacuated glass tube of volume 200cm^3 is filled with a gas at 300k and 101kPa the mass of the tube increases by 1.06g.
What is the identity of the gas?
A) Argon
B) Krypton
C) Neon
D) Xenon
I’m mind blown right now😂😂 that’s such an important pointer right there
Thank you so muchhh. I tried to research about any relationship between the equilibrium pressure and atmospheric pressure , but I couldn’t .
My Pleasure 😊😊I’m mind blown right now😂😂 that’s such an important pointer right there
Thank you so muchhh. I tried to research about any relationship between the equilibrium pressure and atmospheric pressure , but I couldn’t .
I can’t access it tho, but thank you anywayMy Pleasure 😊😊
Yeah it doesn't appear much in textbooks but here's where I trust that you will find it
Its a textbookOpenStax | Free Textbooks Online with No Catch
OpenStax offers free college textbooks for all types of students, making education accessible & affordable for everyone. Browse our list of available subjects!openstax.org
Thanks . Do you have like extremely accurate notes according to the syllabus ? Or where I can get them from ? Thank you in advance .OpenStax | Free Textbooks Online with No Catch
OpenStax offers free college textbooks for all types of students, making education accessible & affordable for everyone. Browse our list of available subjects!openstax.org
Try oalevelnotes.comThanks . Do you have like extremely accurate notes according to the syllabus ? Or where I can get them from ? Thank you in advance .
c i) a yellow flame is seen . Since there's presence of the Sodium Ion so we expect the colour change when sodium is burnt ...
Appreciate it.👍🏻👍🏻Try oalevelnotes.com
View attachment 65271
hello , can anyone please construct a Hess Cycle for me based on this
Thank You . May He Bless you too👏🏻 👏🏻
👏🏻 god bless you .
In the Transformation of carbon and hydrogen to ethyne we need 2 moles of Carbon and 1 mole of hydrogen . The other mole of hydrogen is not used in the reaction and hence the change in enthalpy of that step is zero . I hope you can see in the pictureBut the problem is , isn’t the entalphy change is only needed for C2H2. Here it gives C2H2 and H2
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