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Sure . lolWaji bhai thori madad tau kro variant konsa hai practical ka?
and 34 hai. Urs?
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Sure . lolWaji bhai thori madad tau kro variant konsa hai practical ka?
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_11.pdf
November 2009, P11. Questions 19, 20 and 21 please.
In 21, I don't understand why there are 5 C=C bonds instead of 6.
2 and 3 should be correct. Because there are very large number of monomers combined in a polymer, the number of moles of a polymer will be much lesser than 1.
u seem to b doing the same paper....do u get q 40??..19)--> its A because C and D are automatically out as they both do not represent cyanate now in Ammonium cyanate charge of NH4 is 1 which means that charge on CNO must be -1.
20) D because Carbon atoms connect to CH3 (there are two such Carbon atoms) and to OH also posses chiral center as they are connected to 4 different groups...
21) its confusing 4 me too
the statement sounds very logical...that if 1 is wrong the answer is C...but i was just wondering that how is the 2nd statement correct?...10^-6??...2 and 3 should be correct. Because there are very large number of monomers combined in a polymer, the number of moles of a polymer will be much lesser than 1.
okk..after reading ur statement again...i hav understood a bit....thnk u!...and the video ..perfectly matches the situation.........2 and 3 should be correct. Because there are very large number of monomers combined in a polymer, the number of moles of a polymer will be much lesser than 1.
option 2 and 3 are correct as compound with molecular mass 88 can be formed using given conditionsu seem to b doing the same paper....do u get q 40??..
thx but i guess the variant was different ....its 12.....thx anyway....option 2 and 3 are correct as compound with molecular mass 88 can be formed using given conditions
1 is omitted because saturated refers to double and triple bonds both, however molecular mass of 88 could be obtained using double bonds but using triple bonds its never possible as carbon numbers is restricted to 4. I think this is the concept
wat does variant in this case refer to??thx but i guess the variant was different ....its 12.....thx anyway....
the mcq paper u were solving is paper 11...i.e paper 1 ,first variant....wat does variant in this case refer to??
the mcq paper u were solving is paper 11...i.e paper 1 ,first variant....
i did 12 ie..........paper 1 ,second variant...the questions are same but the order is different in both papers....
Option 3 says that Ca ions react with acids ( hence the equilibrium will shift to the right, decaying the tooth)I still don't get why you're even mentioning carbonic acid. :/
If you've studied bio, you'd know it's usually lactic acid that that forms in the teeth. I feel I'm missing something?
group II metal nitrate is going to produce metal oxide and nitrogen dioxide gas,the ratio between metal nitrate and metal oxide would be 1:1
5/x+28+96 = (5-3.29)/x+16
equate it u will get the answer
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