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Chemistry: Post your doubts here!

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Use of the Data Booklet is relevant to this question.
Which element is likely to have an electronegativity similar to that of aluminium?
A barium
B beryllium
C magnesium
D strontium
why is it B....how?

I remember my Chemistry teacher told me that right adjacent elements share much of the same properties, so only beryllium is on right side of aluminium
 
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someone please help in the following questions
june 2007, p1 . Q 34, 36, 37
nov 2007, p1, q35
june / 07-
Q 37 coz
1. energy is hs to b takn in to brk da bond, thrf endothermic
2. activation energy is high cz stng bnds btween N2..
3 N2 had tripl bonds. so bond energy is high!!!
ANS: A
 
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A monomer undergoes addition polymerisation. A 1 mol sample of the monomer is completely
polymerised.
How many moles of polymer might, theoretically, be formed?
1.1
2 .10–6
3.6.02 1023(avogadro's constant)
 
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A monomer undergoes addition polymerisation. A 1 mol sample of the monomer is completely
polymerised.
How many moles of polymer might, theoretically, be formed?
1.1
2 .10–6
3.6.02 1023(avogadro's constant)
If 1 mole of a monomer is polymerized and you obtained the same number of moles of a polymer, then technically... you got the same thing right? So 1 can't be a polymer. 2 and 3 are just random numbers given but they can be polymers because they're not the same # of moles as the monomer.

So C is right.
 
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Can someone please explain these paper 1 questions?
Thanks.....

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w11_qp_11.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w11_ms_11.pdf
Q8 Why cant the answer be C?
Q16?
Q27 Why is the ratio 3:1?
Q36?

And why isnt the examiner report for this paper available here?

8) because acids give away H+ ions not gain them. look at the backward reaction in equation 2.

27) ultraviolet light means a free radical reaction takes place and this involves HOMOLYTIC fission. Then there are 6 places from where Cl can attack the H to form 1-chloro-propane but only 2 places for attack to form 2-chloro-propane. Thus the 3:1 ratio.

Hope this helps. Good Luck. :)
 
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please tell me how to do this question..i dont knw how many times i"ve posted it! but no one has answered it yet :(
its Q 22 of jun11/11 if you need to refer to the paper. answer is A. PLEASE HELP ME OUT!!
 

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y dos the bond length increase btween hydrogen chloride,hydrogen bromide and hydrogen iodide?
 
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