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Chemistry: Post your doubts here!

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I've read your previous discussion about the question and I see why you don't understand.
The question asks for ANY isomer with C4H8 and with a double bond other than the one shown in the diagram.
The diagram shown is just one example, you can ignore it when drawing other isomers
Like I said before, the 3 isomers are
cis pent-2-ene
trans pent-2-ene
pent-1-ene
Answer is therefore C.3 isomers
it says C4H8..so where the pent 2 ene and pent 1 ene isomers come form? sorry im going a little crazy here :/
 
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Q2) First of all, we know CS2 is the limiting reactant
So 10 cm3 CS2 needs 30 cm3 O2 (See molar ratio)
That means 50 - 30 = 20 cm3 O2 is left after the reaction
Further,
10 cm3 CO2 and 20 cm3 SO2 are produced (See molar ratio)
So total volume of gases left after burning = 20 cm3 O2 + 10 cm3 CO2 + 20 cm3 SO2 = 50 cm3

The answer must be either C or D

Adding NaOH will neutralise (or remove) acidic gases
It will remove 10 cm3 CO2 and 20 cm3 SO2 = 30 cm3 acidic gases
Gas left after NaOH is added = 50 - 30 = 20 cm3

So, C is correct!

Q4) you have add the atomic number of hydrogen carbonate (HCO3-)
H= 1, C=6, O=8
So number of electron of anion = 1+6+(8*3)+1 = 32
The extra 1 is because the anion has a one extra electron that's the reason it has an overall charge of -1 so you have to add that too.
Option C is correct

Q14)14.jpg
 
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Its false.. a triple bond has 1 sigma bond and 2 pi bond.

Really? Wouldn't that mean it has 5 bonds then? Because one pi bond has 2 bonds, so 2 pi bonds... That's 4 bonds already. Then a sigma on TOP of that? Or am I making a mistake somewhere?
 
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