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For B, two products will be formed? How will CH2CCl3 be formed?Asalam alaikum brother.
Is the answer A?
In questions like these you have to keep in mind ALL the products that would be produced if the reactant is mixed separately with the substance in the options and all the required conditions are met.
I'll start with the incorrect one's first.
B) HCl; keeping our knowledge of organic chemistry in mind, this will be an addition reaction, in which the double bond will be changed into a single bond, giving room for the H and Cl to attach to DIFFERENT carbon atoms.
The products will be:
-> CH2CCl3
-> CHCl2CHCl2
Neither are chiral, lets move on to C.
C) NaCN; this would again lead to an addition reaction (nucleophilic), but if memory serves me, it only happens when there is a carbonyl group attached to a carbon atom. Incorrect.
D) NaOH; again, a nucleophilic substitution will occur BUT the C-C double bond will still remain, and for a carbon atom to be chiral it MUST have 4 different alkyl groups/atoms attached to it. Incorrect.
Now for the correct option, A.
Br2.
This will be an electrophilic addition reaction which involves the forming of a carbon cation thus resulting in the breaking to the double bond.
The only product will be:
-> CHClBrCCl2Br
Which is indeed chiral.
Do forgive me if I wrote anything incorrect. Allah knows best.