- Messages
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- Reaction score
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- Points
- 123
Only Part i was what i found to be difficult..
CH3(CH2)4CH(OH)CH=CHCHO
The double bond will be broken .. since both ends have 1 alkyl group and 1 h attached .. Aldehyde will be produced as both the products..
First part CH3(CH2)4CH(OH)CH
Becomes CH3(CH2)4CH(OH)CHO
since CHO can be oxidized further..
CH3(CH2)4CH(OH)COOH
since OH can be oxidized as well..
CH3(CH2)4C(O)COOH First Product
Second Part .. CHCHO
It becomes Aldehyde at both ends .. HOC-CHO
Further oxidizing gives us .. HOOC-COOH Second Product..
Part ii
PCl3 only reacts with OH. so replace OH with Cl..
CH3(CH2)4CH(OH)CH=CHCHO becomes CH3(CH2)4CH(Cl)CH=CHCHO
Part iii
It is a reducing agent.. the only thing which can be reduced is the aldehyde at the end .. since aldehyde gets reduced to primary alcohol..
CH3(CH2)4CH(OH)CH=CHCHO becomes CH3(CH2)4CH(OH)CH=CHCH2OH