- Messages
- 233
- Reaction score
- 90
- Points
- 38
in the first question , where there is NH2 that mean that's where the Br was because this reaction is a nucleaphilic substitution reaction so the nucleaphile which is the NH3 will displace the weaker nucleaphile which is the Br and a hydrogen will replace the other bromine , so from the diagram given if you count from left to right the NH2 is present in the 5ht position , which means in it's place there was a Br so the only answer with a Br in the 5th carbon atom is D, that's how I figured it out , but maybe there's another way , but I hope you understood , you should start by drawing the displayed formula of the options given I suppose. In the second question an increase in pressure in the left container will push the mercury so it's level rises to the right, right?when we increase the temp. for the first reaction the equilibrium will shift to the left hand side where there is more number of moles so more pressure , in the second reaction the number of moles on both sides of the equation is the same so where ever the position of equilibrium goes the same number of moles will occupy the container , thus there is no increase in pressure and obviously in the third reaction it will make the mercury level rise to the left which is not what we want. the third question the kc of the reaction was 2:1 right?(it's given in the question)so in the second reaction they switched the reactants so the kc becomes 1:2 PLUS the number of moles is half so it should be the square root of the Kc so it would be the square root of 1/2 which is A . note: if the kc is equal to 2 this mean it's 2/1 beacuse kc is the ratio right? you might ask why we should put the square root of the answer and not divide the new kc by 2 (because the mole number in the second equation became half) and the answer for that I really don't know hehe , may be it's sort of a rule in ratios or something. hope you understoodcan u answer plz ...
i posted it several times but no one answered