http://papers.xtremepapers.com/CIE/...d AS Level/Chemistry (9701)/9701_w05_qp_1.pdf
Can anyone help me with questions 31,33,35,39?
Can anyone help me with questions 31,33,35,39?
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thanks!Yeah we balance.
Pb(C2H5)4 + 13.5O2 = PbO + 8CO2 + 10H2O
Therefore 1 mol requires 13.5 mol of O2.
question number 31http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w05_qp_1.pdf
Can anyone help me with questions 31,33,35,39?
q4 butene will convert into 1,2-dihydroxybutane(v). the secondary -OH will oxidise to =O and primary -OH will oxidise to -COOHhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w11_qp_22.pdf
q4 : V to W please can somebody explain! also (b)
q5
help plzz
9701.mj.06 q, 25
9701.on.06 q,37,3
9701.mj.01 q 34,26,
9701.on.07 q 33,37,4
9701.mj.08 q 27 ,
9701.on.09 ( varient 11) 28,24,21
9701.on.10(varient 12) 39,27,13
9791.0n.10 (varient 11) q 38 ( what product will form if tollen reagent react with it ),35,29
9701.mj.10 (varient 11) q 12,
9701.mj.11(varient 12) q 38,29,28,24,11,
*9701.mj.11(varient 11) q 36,27,34,26,16
9701.on.11.(varient 12) q 9
9701.on.11 (varient 11) q 27,29,21,
9701.mj.12, (varient 12) q 24,23
9701.mj.12 (varient 11) q 29,23,22,9,
9701.on.12 (varient 11) q 26,
there are two c=c so two moles of Br2 are required to react completely. and (separately) 2 mol of h2 are required.
Thanks ,Aaah. Just did this 5 mins ago
Okay so basically, first things first, you gotta realize that 3 water molecules will be lost, so the Mr of the fragment[gly-ala-ser since equal amounts] will become (75+89+105-(18*3)) = 215.
Dividing 600,000 by 215 will give you the number of fragments present. I'm carefully choosing my words here. Fragments. Not residues. Each of these fragments will have 3 residues so the total fragments present * 3 = number of residues.
Mathematically,
600,000/215 = 2791 fragments
2791 fragments = 2791*3 residues = 8373 residues.
there are two c=c so two moles of Br2 are required to react completely. and (separately) 2 mol of h2 are required.
quote="Suchal Riaz, post: 745892, member: 15977"]there are two c=c so two moles of Br2 are required to react completely. and (separately) 2 mol of h2 are required.[/quote]
Thanks ,
if you can little more expand " fragments and residues " ,
i mean whats the difference , we use the word fragments only in mass spectrometer
Which varient will you be doing this yr ?Each 'fragment' in this example comprises of 3 'residues'. Makes sense now?
12 22 34 42 52Which varient will you be doing this yr ?
q4 butene will convert into 1,2-dihydroxybutane(v). the secondary -OH will oxidise to =O and primary -OH will oxidise to -COOH
q5 do you want full question answered?
so do
A!
This is a pretty simple question which idk why a lot of students have trouble answering.
Tackle it like this.
If the compound was an alkane and had no rings or double bonds, number of H atoms present = 2n+2 = 2(20)+2 = 42
Now, every time there're 2H less, you'll either have a double bond or a ring. The question states that there's one aldehyde (C=O) and 1 ring structure which has 1 C=C so this accounts for 6 missing Hydrogens, thereby leaving you with 8 missing Hydrogens.
8/2 = 4 Hydrogens in the aliphatic side chain.
However, total C=C are 5 because you have to include the C=C from the cyclohexene + cis formation hence A
View attachment 39292
Meaning of Cl being inside ?
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