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Chemistry: Post your doubts here!

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it was trickier than most people here think it was
I can bet my life most people got the Electrode Potential Wrong
Seemed simple I know
Wasnt exactly what it seemed.
I could go on and on about the various small stuff in the paper which people are presuming to be easy and werent exactly straightforward but paper discussion is not allowed.

I couldn't have said it any better. The paper had a looooot of places people could skim thru and mess up. Got me too in one of the questions, had to fix it while rechecking. People have made a lot more tiny 1-2 mark mistakes than they think so this should help neutralize the GT. That said, the GT will most definitely be higher than the mean +Sd I calculated and posted here some time ago. And I've seen GTs touch 70 so it's very much possible. I believe ON13 had a variant with 68 or 69 itself.

We are done with paper 41
We can start discussion

Regardless, there's a third variant too. 24 hours. Is that too much to ask :p
 
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oh i thought since concentration of PbCl2 was lesser than 1 moldm-3, the equilibrium will shift to the left, making Ep more negative.
 
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oh i thought since concentration of PbCl2 was lesser than 1 moldm-3, the equilibrium will shift to the left, making Ep more negative.
Shifting to left won't make it more positive?
It was Pb+2+2e gives Pb so Pb concentration less will cause the reaction to go In backward direction making Eo positive,that's what i thought.
 
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For starters, Lattice Energy can be either positive or negative. Depending on wether youre talking about bond breaking or bond formation. However with reference to how the Born Haber Cycle was formed in that question, Lattice Energy was exothermic.
Secondly, the electrode potential was -0.19V
Reason?
The reduction potential of 1 mol/dm3 was -0.13
Pb2+ + 2e <----> Pb -0.13V
Since the concentration is less than 1 mol/dm3, the equlibrium will shift to the left and think about it this way. It will be even more difficult to reduce so reduction potential will further decrease
Hence 0.19
Now for graph
first of all graph ended at 12.5. Final pH was 12.5
Inital ph was I think, if I remember correctly, 2.8
There would be a very small steep graph initally as the acid was weak
Then a buffer would be formed so slow rise in pH until 10 cm3
Steep vertical portion at 10 cm3
End point above 7
Finally pH would be 12.5
I found Question 1 Part 2 a little difficult
Didnt know what to write
Also the question where he converted -CONH2 to -CH2NH2
I thought about it
Hes reducing
So I just used LiAlH4, not NaBH4, since NaBH4 since it is weak. And I was right.
 
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I had a couple of friends come out of the paper claiming paper was extremely easy and all that
They didnt even know that to prove that Sn and Pb react with oxidising and reducing agents differently, we had to quote Standard Electrode Potentials
They just wrote since the +4 oxides are less stable down group four and stuff
Paper was easy but only for those who knew syllabus inside out.
So dont be scared guys
GT wont be that high
There will be hardly any 'shocking' grades
If you did good
You will get your just reward
 
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my pH was coming as 11. How many marks will I lose. and can Sn and Hcl be used for reduction.
Honestly, not quite sure
depends on where you made the mistake
ecf might get you marks
as for reducing agent
agreed Sn + HCl is a reducing agent
but im not someone you should be asking
I was as surprised as you are and checked LiAlH4 from the net
 
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Honestly, not quite sure
depends on where you made the mistake
ecf might get you marks
as for reducing agent
agreed Sn + HCl is a reducing agent
but im not someone you should be asking
I was as surprised as you are and checked LiAlH4 from the net
Can KI be used as a reducing agent in Sn reaction?
 
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