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Video of June 2011 is uploaded.
Video of June 2011 is uploaded.
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How do you get mole of H2 and O2 please explain?????Here you need to know two concepts/formulas:
mole fraction = number of moles of molecule A / total number of moles
Partial pressure of A = mole fraction of A x total pressure
If 20% of steam had been converted to hydrogen and oxygen, there must be 80% of steam left. So, if you before had 1 mole of steam, you now have 0.8 moles of steam (80% of 1.). Because of the 2:2:1 ratio in the equation, 2H2O ---> 2H2 + O2 , if 0.2 moles of steam had been converted into its products, then by simple stoichiometry the change for H2 is +0.2 and for O2 +0.1.
So you now have the moles of each substance present at equilibrium. If you now use the formulas from the beginning, to calculate the partial pressure, you would see you need the mole fraction of your gas and the total pressure. So, mole fraction = number of moles of molecule A / total number of moles
For steam, you have 0.80 moles, for H2 0.20 and for O2 0.10. If you add them up this give 1.1 - the total number of moles. Therefore, the mole fraction of steam is 0.80/1.1, for H2 is 0.20/1.1 and for O2 is 0.10/1.1. To get the partial pressure of each gas you now times the mole fraction of each substance by the total pressure at which the experiment is done - 1 atm. Hence for steam the partial pressure is 0.8 x 1 / 1.1 and so on...
Hope it helps.
6:B because the graph will move to the left with its peak becoming higher (hence A will move up) but to maintain the number of particles, B and C will have to move down because the number if particles having a lower energy will increase and those having higher energies will decreasehttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s11_qp_12.pdf
can anyone kindly explain:
q6 10 11 23 26
Its A
sorryIts A
1 aldehydes and ketones actually contain the same no of C and H so its defiantly a yes
The 2 gases produced at the anode are oxygen and carbon dioxide , the equations are
Al2O3
invisible :/http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w05_qp_1.pdf
Q1-c
i got D cz pb(c2h5)4 +o2 -->pbo + co2
2*4=8 c and 5*4=20h on react side so if we balance i got 8 oxy frm co2 and 10 oxygens from h2o n 1 oxy from pbo total 27 :/
Q4-c (explain it)
Q6-a (h2=hr-h1 so -395+297=-98 so y is it a ?)
Q12-d (i wrote the eq n for mg n s it is 1 mol of o2 n for al it is 3 moles (3o2) so y is the curve for s the highest ie ans shud be c ) :/
Q20-b (plz write the isomers )
Plz help
Q1Am i
invisible :/
Yeah thanks tht helpedQ1
Pb(C2H5)4 +O2= 8 CO2+10 H2O+PnO3
this is the formula what about H2O??
Q4 C as Hydrogen atom is attached to Oxygen atom
Q6
Because of the moles
the enthalpy change is -297 then 1 mole of SO2 is formed but we need 2 moles to be formed and so enthalphy change wil be (-297*2)
and so for the SO3 it will be (-395*2)
now do you your calculations
Q12 with Mg it is 1/2 mole O2 Mg+1/2O2=MgO
with Al it is 3/4 O2 Al+3/2 O2= 1/2 Al2O3
with Sulpur it is 1 mole of O2 S+O2=SO2
Q20
CHCl=CHCl
CH2=CCl2
And a cis trans
for CHCl=CHCl
like in one of them H will be on the top while in another at the bottom for the second carbon
we have 1/2 3/4 and 1Yeah thanks tht helped
Bt a small doubt for q-12 u said for sulphur only 1 mol of o2 is used ryt n thts wt i said too bt in the graph it says sulphur used the most moles o o2 as the curve for S is the highest
Besides im impressed by the explantion of q1 cz there is no suh thing pno3 n i managed to get the ans by myself we divides 27 by 2 n ans is 13.5 cz o2 molecule has a 2 so tht would be something lile 13.5 * 2 = 27Q1
Pb(C2H5)4 +O2= 8 CO2+10 H2O+PnO3
this is the formula what about H2O??
Q4 C as Hydrogen atom is attached to Oxygen atom
Q6
Because of the moles
the enthalpy change is -297 then 1 mole of SO2 is formed but we need 2 moles to be formed and so enthalphy change wil be (-297*2)
and so for the SO3 it will be (-395*2)
now do you your calculations
Q12 with Mg it is 1/2 mole O2 Mg+1/2O2=MgO
with Al it is 3/4 O2 Al+3/2 O2= 1/2 Al2O3
with Sulpur it is 1 mole of O2 S+O2=SO2
Q20
CHCl=CHCl
CH2=CCl2
And a cis trans
for CHCl=CHCl
like in one of them H will be on the top while in another at the bottom for the second carbon
There such thing as called PbO3 it was typoBesides im impressed by the explantion of q1 cz there is no suh thing pno3 n i managed to get the ans by myself we divides 27 by 2 n ans is 13.5 cz o2 molecule has a 2 so tht would be something lile 13.5 * 2 = 27
Thx anyway
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