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Chemistry: Post your doubts here!

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To wat time r u available today,sir :)

Its nearly 9pm here. I think at most i would stay is till 11pm. Even so, i would only check in occasionally instead of staring at the CPU throughout.

It there are too many questions, I might only focus on those that were not answered before, cause some questions are repeated, students can find them answered by doing a search.
 
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upload_2014-6-7_13-31-20-png.44979

can anyone how to solve ques 12 View attachment 45157
ZaqZainab this is how to solve :p
 
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well bro why did you take values of water and ethyl ethanoate as 1?
questions says that there are one mole of water and ethyl ethanoate. :p
and when Kc has no units or when the volume of concentration cancel out, moles can be used in the equation.
[a]/[c][d] = (n(a)n(b)/V)/(n(c)n(d)/V) volume will cancel out giving number of moles only.
 
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questions says that there are one mole of water and ethyl ethanoate. :p
and when Kc has no units or when the volume of concentration cancel out, moles can be used in the equation.
[a]/[c][d] = (n(a)n(b)/V)/(n(c)n(d)/V) volume will cancel out giving number of moles only.
In the question it doesnt say one mole of water o_O
 
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t
In statement 1, 2 moles of ethanoic acid will react with 1 mole of calcium ion as charge on calcium is +2. So compound will be Ca(CH3CO2)2 which has empirical formula CaC4H6O4.
In 2 and 3, both H from CO2H will be removed so empirical formula will be CaC4H4O4 and not CaC4H6O4.
thanku
 
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