Chemistry: Post your doubts here!

[♣♠ Magnanimous ♣♠]

what is the shape of Xenon tetreflouride and how can we find out the shapes of different compounds?

The shape is Square planar.
Well all the shapes depends mainly on lone pairs and bond pairs

 

[janasalem]

is this in the As level syllabus coz they dont mention this type of geometry

 

[♣♠ Magnanimous ♣♠]

is this in the As level syllabus coz they dont mention this type of geometry

Well it is not mentioned in book
But is this in paper? or in something else?

 

[♣♠ Magnanimous ♣♠]

Can anyone solve this -->
A 6.90 M solution of KOH in water contains 30% by mass of KOH. Calculate the density of the
KOH solution?
[Molar mass of KOH = 56 g mol –1]

plzz

RoOkaYya G

 

[janasalem]

no it's a question in the book
how about this question
Number 7

http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_w10_qp_11.pdf

 

[RoOkaYya G]

RoOkaYya G

u tagged me? i dint get any alerts

 

[RoOkaYya G]

Can anyone solve this -->
A 6.90 M solution of KOH in water contains 30% by mass of KOH. Calculate the density of the
KOH solution?
[Molar mass of KOH = 56 g mol –1]

plzz

is the answer 1.3?

 

[♣♠ Magnanimous ♣♠]

u tagged me? i dint get any alerts

 

[♣♠ Magnanimous ♣♠]

is the answer 1.3?

Show me your solution.

 

[♣♠ Magnanimous ♣♠]

u tagged me? i dint get any alerts

Hey I have one doubt.
Does double bonds affect the bond angle?

 

[RoOkaYya G]

Hey I have one doubt.
Does double bonds affect the bond angle?

yes it does

 

[♣♠ Magnanimous ♣♠]

yes it does

How
I mean bond angle decreases right?
if yes than which will affect more lp lp bonding or double bond on bond angle.

 

[♣♠ Magnanimous ♣♠]

Show me your solution.

RoOkaYya G

 

[RoOkaYya G]

Show me your solution.

6.90 mol * 56 g/mol = 386.4

386.4 g ---> 30 % (0.3)
386.4 --->0.3
x = 1288 g

density of the solution ---> 1288 g / 1000 mL = 1.288 =1.3

 

[♣♠ Magnanimous ♣♠]

6.90 mol * 56 g/mol = 386.4

386.4 g ---> 30 % (0.3)
386.4 --->0.3
x = 1288 g

density of the solution ---> 1288 g / 1000 mL = 1.288 =1.3

NOO! not like this
6.90 M is molarity
now solve it.

 

[RoOkaYya G]

How
I mean bond angle decreases right?
if yes than which will affect more lp lp bonding or double bond on bond angle.

i think lp lp coz itll affect those who r unpaired normally

 

[RoOkaYya G]

NOO! not like this
6.90 M is molarity
now solve it.

-_- i knw. thts how it is.

 

[♣♠ Magnanimous ♣♠]

-_- i knw. thts how it is.

which formula you used..
and

6.90 mol * 56 g/mol = 386.4

386.4 g ---> 30 % (0.3)
386.4 --->0.3
x = 1288 g

density of the solution ---> 1288 g / 1000 mL = 1.288 =1.3

I am getting 2.3

 

[♣♠ Magnanimous ♣♠]

i think lp lp coz itll affect those who r unpaired normally

Number 7

http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_w10_qp_11.pdf

 

[RoOkaYya G]

which formula you used..
and

I am getting 2.3

molarity * molar mass = mass of the KOH in the solution
since 30 is the KOH there
so the mass represents 30 %
so 0.3 ---> 56 * 6.9 = 386.4 g
so per percent its 386.4 / 0.3 = 1288 g (using ratio to compare)
so density = mass / volume = 1288 / 1000 = 1.28