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The shape is Square planar.what is the shape of Xenon tetreflouride and how can we find out the shapes of different compounds?
Well all the shapes depends mainly on lone pairs and bond pairs
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The shape is Square planar.what is the shape of Xenon tetreflouride and how can we find out the shapes of different compounds?
Well it is not mentioned in bookis this in the As level syllabus coz they dont mention this type of geometry
RoOkaYya GCan anyone solve this -->
A 6.90 M solution of KOH in water contains 30% by mass of KOH. Calculate the density of the
KOH solution?
[Molar mass of KOH = 56 g mol –1]
plzz
u tagged me? i dint get any alerts
is the answer 1.3?Can anyone solve this -->
A 6.90 M solution of KOH in water contains 30% by mass of KOH. Calculate the density of the
KOH solution?
[Molar mass of KOH = 56 g mol –1]
plzz
u tagged me? i dint get any alerts
Show me your solution.is the answer 1.3?
Hey I have one doubt.u tagged me? i dint get any alerts
yes it doesHey I have one doubt.
Does double bonds affect the bond angle?
Howyes it does
RoOkaYya GShow me your solution.
6.90 mol * 56 g/mol = 386.4Show me your solution.
NOO! not like this6.90 mol * 56 g/mol = 386.4
386.4 g ---> 30 % (0.3)
386.4 --->0.3
x = 1288 g
density of the solution ---> 1288 g / 1000 mL = 1.288 =1.3
i think lp lp coz itll affect those who r unpaired normallyHow
I mean bond angle decreases right?
if yes than which will affect more lp lp bonding or double bond on bond angle.
-_- i knw. thts how it is.NOO! not like this
6.90 M is molarity
now solve it.
which formula you used..-_- i knw. thts how it is.
I am getting 2.36.90 mol * 56 g/mol = 386.4
386.4 g ---> 30 % (0.3)
386.4 --->0.3
x = 1288 g
density of the solution ---> 1288 g / 1000 mL = 1.288 =1.3
Number 7i think lp lp coz itll affect those who r unpaired normally
molarity * molar mass = mass of the KOH in the solutionwhich formula you used..
and
I am getting 2.3
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