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Ahhh... Now I get it.. Thank you!CH4 + Cl2 = CH3Cl + HCl
Cl2 reduced to form Cl(-).
C(4-) in CH4 oxidized to C(2-) in CH3Cl.
Hope this helped.
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Ahhh... Now I get it.. Thank you!CH4 + Cl2 = CH3Cl + HCl
Cl2 reduced to form Cl(-).
C(4-) in CH4 oxidized to C(2-) in CH3Cl.
Hope this helped.
Can u explain clearly why 2nd is wrong? I did the calculation for it like if we're going from T to S we can use T-U and U-S so (-75+92=+17) the answer is + so can be endo, no?It's easy, just follow the instructions, it says from U to R which means the direction would change (arrow) and positive enthalpy would be reversed by sign. whereas 2nd option is wrong because endothermic is donated by +ve sign
could anyone explain Q3(c)(i)(ii)?
in paper 5 of chemistry?plz tell me what to do with the construction lines in paper ? :/
Is it A?View attachment 49036
Can someone explain this to me ?
From T-U it is (-75 kJ/mol) and as from U-S the the direction of arrow will be changed so the value would be (-92 KJ/mol) so total value has -ve sign with it this shows it is exothermicCan u explain clearly why 2nd is wrong? I did the calculation for it like if we're going from T to S we can use T-U and U-S so (-75+92=+17) the answer is + so can be endo, no?
D is a tertiary halogenoalkane, they undergo Sn1 nucleophilic substitution (the Br breaks off and then, very quickly, OH- replaces it) and so the rate determining step is the Br bond breaking (and thus dependent on the concentration of the organic molecule only); since the substitution of OH- is very fast compared to it, adding more OH- does not increase the rate.Can someone please explain
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s10_qp_12.pdf
Q26 (Ans: D)
Thank you
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