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Why would the ratio be 3:1??
Why is 3 wrong? If something can form H-bonds then it will mix right?
Why would 3 also occur?
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Why would the ratio be 3:1??
Why is 3 wrong? If something can form H-bonds then it will mix right?
Why would 3 also occur?
well this is done in the same manner..
How to do this??
How did you get n of 2NO2 + O2 as 0.014?Sr(NO3)2 ------> SrO + 2NO2 + 1/2 O2
n of Sr(NO3)2 =0.014
n of 2NO2 + O2 = 0.014
Help please........ qwertypoiu can you please explain me this question, like why cant the Answer be C? is there anything else behind the unbalanced part ... as i have even asked this question before but didnt get a good response ..
Which of these equations represents the reaction of sulphur dioxide with an excess of aqueous
sodium hydroxide?
A SO2 + NaOH ----> NaHSO3
B SO2 + 2NaOH -------> Na2SO3 + H2O
C SO2 + 2NaOH ------> Na2SO4 + H2O
D SO2 + 2NaOH -----> Na2SO4 + H2
total mass = 108How did you get n of 2NO2 + O2 as 0.014?
As fantastic girl has already said,Help please........ qwertypoiu can you please explain me this question, like why cant the Answer be C? is there anything else behind the unbalanced part ... as i have even asked this question before but didnt get a good response ..
Which of these equations represents the reaction of sulphur dioxide with an excess of aqueous
sodium hydroxide?
A SO2 + NaOH ----> NaHSO3
B SO2 + 2NaOH -------> Na2SO3 + H2O
C SO2 + 2NaOH ------> Na2SO4 + H2O
D SO2 + 2NaOH -----> Na2SO4 + H2
no shaz
SO3 + NaOH -----> Na2SO4 not when SO2 rects wid NaOH
check notes buddy
Thanks both of youAs fantastic girl has already said,
NaOH, when reacting with SO2, initially produces Na2SO3.
It may later get oxidised to Na2SO4 however.
Ma pleasureThanks both of you
First of all we Balance the 2nd equation inorder to cancel the electrons from both the Eqns...
balance equation 2 to get 4e- nd this will give 2 moles of I2
so the ratio will be 1:2
Thanks,mind explaining these as well:First of all we Balance the 2nd equation inorder to cancel the electrons from both the Eqns...
Therefore we multiply 2nd eqn by 2 to get 4 electrons which can be cancelled ... then the final eqn would have 1 mole of IO3- and 2 moles of I2
Thanks,mind explaining these as well:
It behaves as an ideal gas so shouldnt the particles be I instead of I2?
HCl is polar,while Ccl4 is not so shouldnt it have higher mp?
I got this but it says it behaves like an ideal gas,so shouldnt it have separate atoms of I instead of atoms that have intermolecular forces like I2Ur welcome
Mr of iodine is 127x2 = 254
PV=nRT
1x10^5 x 1.247x10^-3 = 6.35/254 x 8.31 x T
T= 600 K
i didnt think abt this :/I got this but it says it behaves like an ideal gas,so shouldnt it have separate atoms of I instead of atoms that have intermolecular forces like I2
Nobel gases have weak van der waals force of attraacton b/w themselvesI got this but it says it behaves like an ideal gas,so shouldnt it have separate atoms of I instead of atoms that have intermolecular forces like I2
And what about the second one?HCl and Ccl4 onei didnt think abt this :/
they said iodine vapour so i went wid the formula I2 :/
Number of electrons in hydrogen chloride molecule = 18And what about the second one?HCl and Ccl4 one
ummm iam not really sureAnd what about the second one?HCl and Ccl4 one
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