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Chemistry: Post your doubts here!

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The Haber process for the manufacture of ammonia is represented by the following equation.
N2(g) + 3H2(g) 2NH3(g) ∆H = –92kJ mol–1
Which statement is correct about this reaction when the temperature is increased?

A Both forward and backward rates increase.
B The backward rate only increases.
C The forward rate only increases.
D There is no effect on the backward or forward rate.

Why is the correct answer A? The reaction in exothermic so by increasing the temperature, won't the backward reaction increase only?
When temp is increased, rate increases for both forward & backward. When they ask you for yield, then you can say yield of Nh3 will decrease.
 
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Which mixtures, on heating, produce the gas ND3?
[D = H 2
1 , an isotope of hydrogen]
1 CaO(s) and ND4Cl(s)
2 CH3CN and NaOD in D2O
3 NDH3Cl and NaOD in D2O

So D is like H so we can suppose NDH3Cl as NH4Cl so wouldnt reaction 3 also liberate ammonia?The Ms says only 1,2 are correct.
 
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I think you have asked similar questions on this? This question is on intermolecular forces of attraction. HCl has the strongest intermolecular attraction (PD-PD) compared to the other options (VDW).




ammonium salt + base --> salt + water + ammonia

It is "bad" because, the nitrogen nutrient which is meant to be taken in by the plants is lost to the surroundings as ammonia gas.
Thankyou! And yes I always keep thinking of the bond energies... :p
 
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Which mixtures, on heating, produce the gas ND3?
[D = H 2
1 , an isotope of hydrogen]
1 CaO(s) and ND4Cl(s)
2 CH3CN and NaOD in D2O
3 NDH3Cl and NaOD in D2O

So D is like H so we can suppose NDH3Cl as NH4Cl so wouldnt reaction 3 also liberate ammonia?The Ms says only 1,2 are correct.

The 3rd reaction doesn't involve D2O ... it is just the reaction between (Ammonium salt) NDH3Cl + (alkali) NaOD ... so we have only 2 D atoms now, but we actually need 3 D atoms to produce ND3 ...
so probably sth like ND2H or sth is produced instead, but that doesn't matter.
 
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The 3rd reaction doesn't involve D2O ... it is just the reaction between (Ammonium salt) NDH3Cl + (alkali) NaOD ... so we have only 2 D atoms now, but we actually need 3 D atoms to produce ND3 ...
so probably sth like ND2H or sth is produced instead, but that doesn't matter.
What do you mean?Then how is 2 correct?
 
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which year is this from?
Which mixtures, on heating, produce the gas ND3?
[D = H 2
1 , an isotope of hydrogen]
1 CaO(s) and ND4Cl(s)
2 CH3CN and NaOD in D2O
3 NDH3Cl and NaOD in D2O

So D is like H so we can suppose NDH3Cl as NH4Cl so wouldnt reaction 3 also liberate ammonia?The Ms says only 1,2 are correct.
 
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I honestly have no idea ... examiners have twisted brains! genius, yes, but twisted.
Can you explain these:
40 Fats and grease that build up on pans used in cooking are esters. Pans which are dirty from fats
or grease may be cleaned by heating them with a reagent that will react with the ester group.
What may be used to clean such pans by this reaction?
1 vinegar - aqueous ethanoic acid, CH3CO2H
2 alcohol - ethanol, C2H5OH
3 baking powder - sodium hydrogencarbonate, NaHCO3


11535213_389818537892743_42899605_o.jpg

11294497_389818514559412_1458365858_o.jpg
 
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The products obtained by cracking an alkane, X, are methane, ethene and propene. The mole fraction of ethene in the products is 0.5. What is the identity of X?

A C6H14
B C8H18
C C9H20
D C11H24

Correct answer is B.
 
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