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Chemistry: Post your doubts here!

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Guys, can somebody help me find the person who made these notes? I found them last year on xtremepapers and these have been immensely beneficial but these are for AS Level. I am looking for the A2 notes in this format. Maybe the author had created the A2 notes also.

For every chapter, there are syllabus points and then concise notes afterwards; very useful.
1.png 2.png
 

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  • Chapter 1 Atomic Structure.pdf
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Guys, can somebody help me find the person who made these notes? I found them last year on xtremepapers and these have been immensely beneficial but these are for AS Level. I am looking for the A2 notes in this format. Maybe the author had created the A2 notes also.

For every chapter, there are syllabus points and then concise notes afterwards; very useful.
View attachment 60198 View attachment 60199
Guys, can somebody help me find the person who made these notes? I found them last year on xtremepapers and these have been immensely beneficial but these are for AS Level. I am looking for the A2 notes in this format. Maybe the author had created the A2 notes also.

For every chapter, there are syllabus points and then concise notes afterwards; very useful.
View attachment 60198 View attachment 60199
You mean you got these from here right?
A2 chapters have been added but not all.I hope that helps.
 
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I'm confused on how to draw the structural formula for B. I know what it will be.20160410_235338.png

This is the mark scheme 20160410_235221.jpg

This is my attempt is it correct?20160410_235242.jpg
 
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You have to play with the numbers to try to deduce the species responsible for each mass peak. Start with the smallest one and build on from there:

133 - SiCl3

I got this by subtracting various mass numbers from 133 on my calculator and this worked.

Next step is 149, which is 16 away, so just add O:

149 - SiCl3O

Next is 247... That's 98 we have to add. Cl2 gives 70, and Si another 28! So:

247 - Si2Cl5O

Then 263.... That's again a leap of 16:

263 - Si2Cl5O2

Next we have 396... 133 to jump! Get rid of 70 again with Cl2. 63 left. The last digit of 63 is 3, and that could be made by numbers ending with 8 and 5. Basically, 28 + 35 = 63. So we add SiCl3 more:

396 - Si3Cl8O2.
 
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