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I used the total volume (70 cm3) to calculate the concentration as it said reaction mixture in the question. Do you think that would be right?
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yeah thats what i did.. i most probably think it is correct.. and btw guys the line dint have to pass thru the origin. i asked the technicians and they told me the mixture had impurities as instructed in confidential instructionsI used the total volume (70 cm3) to calculate the concentration as it said reaction mixture in the question. Do you think that would be right?
i forced my graph to pass through origin and i only had one point on my graph and all the other points were close to my graph but not on my graph....yeah thats what i did.. i most probably think it is correct.. and btw guys the line dint have to pass thru the origin. i asked the technicians and they told me the mixture had impurities as instructed in confidential instructions
anyways all is not lost.. it may be wrong but i doubt it cos the supervisor told me..i forced my graph to pass through origin and i only had one point on my graph and all the other points were close to my graph but not on my graph....
Really??? All students in my centre had their graph passing through the origin and with points near or on the line.anyways all is not lost.. it may be wrong but i doubt it cos the supervisor told me..
well i dint exactly ask them.. my teacher asked them and told me.., but whatever we say we cant change anything so lets forget itReally??? All students in my centre had their graph passing through the origin and with points near or on the line.
well i dint exactly ask them.. my teacher asked them and told me.., but whatever we say we cant change anything so lets forget it
maybe you'll lose only one mark!My line didn't pass through the origin? :/
Phew! :/
1. Less surface area, so quick time.
2. 0.03 concentration
3. Directly proportional.
i multiplied the errors by 2 then divided by the respective volume and multiplied by 100!
for concentration i first got 0.03. then i realised that u had to use the total volume which included volume of acid used, so then i got 0.021 moldm3.
Yes that's right but wasn't the total volume 50 cm3 not 70?I used the total volume (70 cm3) to calculate the concentration as it said reaction mixture in the question. Do you think that would be right?
the uncertainty question is similar to the one in nov 2007! when my teacher corrected it, he multiplied by 2.. i forgot the explanation he gave :/Why did you multiply the errors by 2?
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