chemistry unit 3 !!! discussion in here !! =p

[DANGERBP]

guyz this one > propan-1-ol + h2so4 concentrated heated under reflux ! identify the main organic product ?

 

[DANGERBP]

welcome and idk myself, it was written in the book :/ srry

oh don worry ! =p amma r8 100 no need to know =p !

 

[U stalking ME]

guyz this one > propan-1-ol + h2so4 concentrated heated under reflux ! identify the main organic product ?

propanoic acid but if distilled immediately then it is propanal

 

[DANGERBP]

oh this one too guyz > kI + h2so4 >> gives wat nd wat r the observations ?

 

[DANGERBP]

propanoic acid but if distilled immediately then it is propanal

=$ i know that =p =p ! lol =$

 

[U stalking ME]

oh this one too guyz > kI + h2so4 >> gives wat nd wat r the observations ?

gives HI and KHSO4.
HI immediately oxidised to iodine. H2SO4 reduced to hydrogen sulfide
observations;
rotten egg smell and turns lead ethonate paper from white to black.

 

[xIshtar]

oh this one too guyz > kI + h2so4 >> gives wat nd wat r the observations ?

Steamy gas, purple vapour, a yellow solid all produced in a vigorous reaction.

 

[DANGERBP]

gives HI and KHSO4.
HI immediately oxidised to iodine. H2SO4 reduced to hydrogen sulfide
observations;
rotten egg smell and turns lead ethonate paper from white to black.

dude but theres yellow solid formed wats it ?
nd the color of the filter is due to HsO2 ?? why lead ethanoate ??
wats the colour os So2 ?
thnks =p

 

[DANGERBP]

Steamy gas, purple vapour, a yellow solid all produced in a vigorous reaction.

wait wat ??

gives HI and KHSO4.
HI immediately oxidised to iodine. H2SO4 reduced to hydrogen sulfide
observations;
rotten egg smell and turns lead ethonate paper from white to black.

??
2 different answers ?? O.O 0.O

 

[DANGERBP]

gives HI and KHSO4.
HI immediately oxidised to iodine. H2SO4 reduced to hydrogen sulfide
observations;
rotten egg smell and turns lead ethonate paper from white to black.

Steamy gas, purple vapour, a yellow solid all produced in a vigorous reaction.

guyz where can i study such rxns ??

 

[U stalking ME]

guyz where can i study such rxns ??

study guide and the book

 

[DANGERBP]

study guide and the book

lol study guid > not check
n my book have nothin like such things
plus whats the answer to tht yours or hers ? =p !

 

[U stalking ME]

wait wat ??

??
2 different answers ?? O.O 0.O

they r all truee
yellow solid- KHSO4
Steamy gas- HI
purple vapour- I2
lead ethonate and rotten egg smell is for H2S
pass through aci.potassium dichromate green to orange then SO2

 

[U stalking ME]

lol study guid > not check
n my book have nothin like such things
plus whats the answer to tht yours or hers ? =p !

wat book do u have??

 

[DANGERBP]

wat book do u have??

pearson ! =p

they r all truee
yellow solid- KHSO4
Steamy gas- HI
purple vapour- I2
lead ethonate and rotten egg smell is for H2S
pass through aci.potassium dichromate green to orange then SO2

oh ! =p !
okay can you tell me wat do we need to know bout the apearance of so2 nd so3
so2 is being oxidised by k2cr2o7 ? thats why ?

 

[U stalking ME]

pearson ! =p

oh ! =p !
okay can you tell me wat do we need to know bout the apearance of so2 nd so3
so2 is being oxidised by k2cr2o7 ? thats why ?

pearson umm the one of edexcel AS chemistry by Ann Fullick and Bob Mcduell??
Cr2O7 2-(aq) + 3SO2 (g) + 2H+ (aq) = 2Cr3+ (aq) + 3SO4 2- (aq) H2O (l)
Test for SO32- Warm the sulphite with dilute HCl. using acidified potassium dichromate(VI) solution (or paper). The solution turns green.
for SO4 2- Add barium chloride solution acidified with dilute HCl to the test solution. White precipitate of barium sulphate forms.

 

[xIshtar]

wait wat ??

??
2 different answers ?? O.O 0.O

2 Identical answers, just with different focuses on the reaction. And we're both right so

H2SO4 is reduced by potassium dichromate to form SO2

Look at the oxidation numbers, +6 to +4.

In SO3 Sulphur is +6 and in SO2 it is +4.

By OILRIG, electrons have been gained, so it has been reduced.

Unless the SO3 has 2- next to it, which you didn't say

 

[DANGERBP]

2 Identical answers, just with different focuses on the reaction. And we're both right so

H2SO4 is reduced by potassium dichromate to form SO2

Look at the oxidation numbers, +6 to +4.

In SO3 Sulphur is +6 and in SO2 it is +4.

By OILRIG, electrons have been gained, so it has been reduced.

Unless the SO3 has 2- next to it, which you didn't say

=S wat happens if it has 2- ?

 

[DANGERBP]

pearson umm the one of edexcel AS chemistry by Ann Fullick and Bob Mcduell??
Cr2O7 2-(aq) + 3SO2 (g) + 2H+ (aq) = 2Cr3+ (aq) + 3SO4 2- (aq) H2O (l)
Test for SO32- Warm the sulphite with dilute HCl. using acidified potassium dichromate(VI) solution (or paper). The solution turns green.
for SO4 2- Add barium chloride solution acidified with dilute HCl to the test solution. White precipitate of barium sulphate forms.

idk man just that =p !
the test for so32- is same as so2 ? ya ?
thankss !
ya whose with the pungent smell again so2 ?? =$

 

[xIshtar]

=S wat happens if it has 2- ?

If it is SO3 2-

Then, S is +4

And thus it has the same charge as that in SO2, as sulphur is also +4 there.

Basically, just make sure you look at charges and ions, to be certain that is oxidised

How is everyone feeling?