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Variant 22 - Question 1 - c - i
In part b iv
The moles of NaOH that reacted with acid are found to be 0.04 moles
So in part c i
Shouldn't the moles at equilibrium be 0.06 moles for the acid and ROH and 0.04 mol for ester and H2O (Since 0.04 reacts and originally 0.1 is present so left over = 0.1-0.04 = 0.06)
The mark scheme says other way round... how?
Variant 22 - Question 1 - c - i
In part b iv
The moles of NaOH that reacted with acid are found to be 0.04 moles
So in part c i
Shouldn't the moles at equilibrium be 0.06 moles for the acid and ROH and 0.04 mol for ester and H2O (Since 0.04 reacts and originally 0.1 is present so left over = 0.1-0.04 = 0.06)
The mark scheme says other way round... how?