Coordinates geometry (add maths)

[Diishiik Douw]

te line joining A(5,11) and B(0,1) meets the x-axis at C. the point P lies on C such that APB = 3:2.

(1) FIND THE COODINATES OF P.

and the other part...i can't draw it..
can someone help me on add maths NOVEMBER 2001 PAPER1 NO 3

 

[abcde]

Yes sure
You can use vectors to find the coordinates of P. AP/PB = 3/2
(OP - OA) / (OB - OP) = 3/2.
Simplifying you get, 5 OP = 3 OB + 2 OA
Since the coordinates of A and B are given you can write them down in position vector form i.e. OA and OB and thus find OP. so here you go....

SECOND PART
First you find the gradient of line PB using their coordinates (duh!). Since the two angles are equal, gradient of line PQ = - gradient of line PB. Then use the formula and write: y - 5 = (gradient of PQ) (x - 2) to obtain the equation. Hope this helps!

P.S. I'm a girl too