Could anyone help me with my following chem doubts? Thx.

[kumiko]

May 94 Q10
Nov98 Q21
Nov2000 Q39

Thankssss

 

[MTH]

May 94 Q10
Nov98 Q21
Nov2000 Q39

Thankssss

Could you give me the link to those papers as I don't have anyone one of them.

 

[kumiko]

Could you give me the link to those papers as I don't have anyone one of them.

Sure

 

[kboss]

Sure

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10 should be D
21... i don't get the question
39 is certainly A.

 

[MTH]

No q 1o is B, you just have to balance the equation. And for q 21 i don't get it as well. Q 39 is A.

 

[kboss]

No q 1o is B, you just have to balance the equation. And for q 21 i don't get it as well. Q 39 is A.

U r wrong its D...look at the eqn. and try balancing the eqn. again.

 

[MTH]

U r wrong its D...look at the eqn. and try balancing the eqn. again.

yes i got the same.

 

[MTH]

i mean I got the same as I got before !

 

[kumiko]

Thanks guys....
The answer on ms for Q10 is B, and I got D.
For Q21 is A and Q39 is A

 

[kumiko]

Could you explain how to get A for Q39???

 

[kboss]

i mean I got the same as I got before !

my bad... i read it as C3H6....

 

[areebaization]

39 is certainly A.

could u explain How is it so? because it says 2 moles of ethane and one mole of methane :S

 

[Saadiya Ahmed]

Could you explain how to get A for Q39???

39 is D
2 molecules of ethene > C2H4 +C2H4= C4H8
Now add methane to it...ull get C4H8 + CH4--> C5H12

 

[NabzJ]

Sure

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qs 21 = D

 

[thats_me]

Sure

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10 : C3H7COONa + NaOH ---> Na2CO3 + ____ (Compare the product with the reactants If u take out Na2CO3 from the reactants wat is left? C3H7 from C3H7COONa & H from NaOH so C3H8
21 : Nitrogen & ammonia are insoluble in water so it's D
39 : ____ ---> 2C2H4 + CH4 (just add them) so C5H12

 

[kumiko]

qs 21 = D

Thanks. Probably the ms is wrong

 

[kumiko]

39 is D
2 molecules of ethene > C2H4 +C2H4= C4H8
Now add methane to it...ull get C4H8 + CH4--> C5H12

I see. THANKS!!!

 

[kumiko]

10 : C3H7COONa + NaOH ---> Na2CO3 + ____ (Compare the product with the reactants If u take out Na2CO3 from the reactants wat is left? C3H7 from C3H7COONa & H from NaOH so C3H8
21 : Nitrogen & ammonia are insoluble in water so it's D
39 : ____ ---> 2C2H4 + CH4 (just add them) so C5H12

Many thanks for your help! Now i understand

 

[thats_me]

Many thanks for your help! Now i understand

Ur most welcum

 

[NabzJ]

Thanks. Probably the ms is wrong

its not wrong the ms says d as i said !! Oct 1998 right ?. I checked its d !!