Diverging/concave lens

[abcde]

AOA!
I could not understand question 22 of this paper: http://www.xtremepapers.net/CIE/Cambrid ... 9_qp_1.pdf
Maybe that's because I do not know the properties of a diverging lens. Can anyone help me out please?
JazakAllah!

 

[abcde]

I also can't really get question 6 of the same paper so please help! :S

 

[OakMoon!]

Since, its a diverging lens, the image that'll be formed will be virtual and on the same side of the object. Make the two light rays as shown in the diagram. The red line is actually a dotted virtual line that is supposed to be passed through the focal point. And the second ray is passed through the center of the lens, the intersection of the two lines is the top of the image. So the answer is B. This is the method of determining the image or the object position in a diverging lens. See the optics chapter of Explaining phyics for better understanding.

 

[Nibz]

I also can't really get question 6 of the same paper so please help! :S

Friction acts to oppose slipping between surfaces. Imagine that coin spinning with the turntable. If there were no friction, where would it tend to go? Since the table is rotating, the coin would go outwards => towards C! but the question says, it remains in the same position ..So, the friction force must be in opposite direction..i.e inwards! (Opposite of C)
So A is the answer!
Hope this makes sense!

 

[OakMoon!]

Its because of the reaction force that the coin will go outwards. So friction force has to oppose it to keep the coin stationary. Nibz has given a very good explanation. The reaction force is actually the reaction for the centripetal force towards the center of the table where the friction force will act.

 

[abcde]

Made perfect sense!