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is the ansQ. If a square prism is inscribed in a right circular cylinder of radius r and height h, the volume inside the cylinder but outside the prism is ....... ?
r^3(pi/(2)^1/2 + 8)
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is the ansQ. If a square prism is inscribed in a right circular cylinder of radius r and height h, the volume inside the cylinder but outside the prism is ....... ?
4 ka ans kia hai?some problems ....... rite here
1.)cos3x=?
a)4cos^3x - 3cosx
b)4cosx - 3cos^2x
c)4cos^2x - 3cosx
d)3cosx - 4cos^2x
2.)convert radian measure 4/(3.pi) to degree measure.
a)24.32
b)24.97
c)1.97
d)4.96
3.)tanx = ??
a) cosx + sinX
b) sinx/cosx
c) (2tan(x/2))(2tan(x/2)/1-tan^2(x/2))
4.)The area of rectangle ABCD is 48, and its peremiter is 28, then AB - Bc is??
a)Not possible
b)12
c)24
d)36
5.)sina =(3^1/2)/2
cosb =(1/(2^1/2))
now (a + b) = ??
a)110 degrees
b)105 degreees
c)100 degrees
d)90 degrees
most of the ans. are known to me but mine donot match the one in book so plz.. help out
not possible.... what do u say??? and wat abt rest??4 ka ans kia hai?
rest ka baad main dekhungi.not possible.... what do u say??? and wat abt rest??
rest ka baad main dekhungi.
and 4 is not possible
area = l*b
perimeter = 2(l+b)
lb=48
l=48/b
2(l+b) = 28
l+b = 14
replace l with 48/b
quadratic equation banegi. solve it
u will get 6 and 8
ab - bc means l - b
8-6 is 2
obviously.han na tou value is present same is mine... but not given in options???? so shud i select not possible??
isnt it 3b?
2 ka ans a hai?sorry bt didnot gt u??? what 2a???
g bilkul.... and sorry no problem in this question... wrote unexpectedly..2 ka ans a hai?
and what abt 5 ka ans? it is 105?2 ka ans a hai?
yes explanation plz???and what abt 5 ka ans? it is 105?
sin inverse and cos inverse lo dono given values ka. u will get a and b respectively. add them.yes explanation plz???
oh well thanx.... i put so much tym on this question using double angle identity i.e sin(a+b)sin inverse and cos inverse lo dono given values ka. u will get a and b respectively. add them.
u must remember some standard values of sin and cos and tan
dun b sad. be happy happy. sb set hoga iAoh well thanx.... i put so much tym on this question using double angle identity i.e sin(a+b)
as i didnot remember the values of sin-1.... til now used calculator.
Too generalistic!(pi)(r)^2(h) - LxBxH
wrongis the ans
r^3(pi/(2)^1/2 + 8)
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