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Enthalpy change of neutralization

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Okay so there is a practical in which you have to find delta H neutralization for naoh and h2so4.i have calculated the heat of the reaction i.e 4945,the moles of naoh i.e 0.09,moles of h2so4 i.e 0.04 now in order to calc delta H what exactly do i have to do divide 4945 by 0.04 or by 0.08 please help and explain..... :%)
 
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