expected grade boundries for As math p12

[thementor]

Can you tell me the exact p question of the last one
I am not remembering it , though I know one of my answer was -4

p was -4 i have checked the answer through a gtaph plotter. the two functions were x^2+4x and 2x-3

 

[Muhammad Arham Ayaz Malik]

I messed up q2 first 2 parts , though I did the last one correct so I cut my 3 marks in total

 

[Snowysangel]

I have the same answers as this guy

Good for you

 

[Muhammad Arham Ayaz Malik]

Tell me q7 od vector plz

 

[thementor]

Tell me q7 od vector plz

As far as my memory tells me it was (8,1,14) I am confirmed about the numbers but I cant seem to remember the signs. Oh well, there's a limit to how much I can remember

 

[Muhammad Arham Ayaz Malik]

I am impressed by your memory , but my answer was 8 ,1,8 and I am pretty surr about the number I dont remember sign

look vector ba was 2 1 2
so the ratio must be same for parrallel vector cd

 

[Muhammad Arham Ayaz Malik]

Cd me oc add krna tha , check your memory for oc
Do you remember OC?

 

[thementor]

The answer to Q8

 

[thementor]

Cd me oc add krna tha , check your memory for oc
Do you remember OC?

OC was (4 5 6)

 

[thementor]

OC was (4 5 6)

Okay yes, now I remember the answer. CD was ( -8 -4 8) and since OC was ( 4 5 6) then OD was ( -4 1 14)

 

[thementor]

I know and I got my mistake. I forgot multiply by -1 when differentiating...so I got the equation of the tangent wrong too (i got -.5 + x wheh it was +.5 + x) and so i got the area wrong too. Is there ecf in p1?

The equation of the tangent of the graph (8 - sqrt(4-x)) was y = 0.5x +5.5. However if your method was partially correct you will get M marks and yes there is an ecf in P1

 

[Shehriyar999]

What was the G.P ratio.Mine was 1/4 since after solving the simultaneous method involving D and R,I got two values (1,1/4). hence since the question say's the ratio is npt equal to 1.the other value 1/4 was to be taken.
Reply ASAP.

 

[Wolfgangs]

In the sequence questions, in part one, we were asked to find common ratio only, right?

 

[thementor]

What was the G.P ratio.Mine was 1/4 since after solving the simultaneous method involving D and R,I got two values (1,1/4). hence since the question say's the ratio is npt equal to 1.the other value 1/4 was to be taken.
Reply ASAP.

The ratio was 1.5

In the sequence questions, in part one, we were asked to find common ratio only, right?

yes

 

[Shehriyar999]

Yes.what was yours?
s

 

[thementor]

What was the G.P ratio.Mine was 1/4 since after solving the simultaneous method involving D and R,I got two values (1,1/4). hence since the question say's the ratio is npt equal to 1.the other value 1/4 was to be taken.
Reply ASAP.

The ratio was not equal to 1 yes. What kind of an equation did you solve. The question was:
The 1st, 2nd and 3rd terms of a geometric progression are the 1st, 9th and 21st terms of an arithmetic progression. The first term of both is 8. The ratio is not equal to 1. Find the common ratio.

 

[thementor]

Yes.what was yours?
s

1.5

 

[snipex]

yes, 2l7 thnx man for sharin answers now Ive checked all my answers and calmed down isa A

 

[Shehriyar999]

I formed 2 equations in terms of D and R. 1) 8r=8+8d and 2) 8r^2=8+20d..Solve it!

 

[snipex]

8r=8+8d
divivde all by 8 it will be r=1+d
then subistitute it in 8r2=8+20d
8(1+d)2=8+20d
8(1+d2+2d)=8+20d
8+8d2+16d=8+20d
8 will cacel with 8 so 8d2+16d-20d=0
take d common d(8d-4)=0
d=0 which is rejected
8d-4=0 which maked d=0.5
put d=0.5 in r=1+d and r=1.5 thats answer