http://papers.xtremepapers.com/CIE/...athematics - Further (9231)/9231_s08_qp_1.pdf
Question 9
Why is the value of lambda assumed to be that?
Thanks!
Question 9
Why is the value of lambda assumed to be that?
Thanks!
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That 1?http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics - Further (9231)/9231_s08_qp_1.pdf
Question 9
Why is the value of lambda assumed to be that?
Thanks!
Perfect, thanks!That 1?
Well, I will solve the whole question for you as soon as my date with chemistry ends up
9)http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics - Further (9231)/9231_s08_qp_1.pdf
Question 9
Why is the value of lambda assumed to be that?
Thanks!
Thank you very much for your response.9)
If the degree is greater in the numerator oblique asymptotes can occur.
y = (x^2 – 2x + λ)/(x + 1) = (x – 2 + λ/x)/(1 + 1/x)
As x tends to infinity the function gets nearer to y = x – 2 independantly of λ.
A useful observation is that λ = 1 makes the numerator (x – 1)^2
dy/dx = (x^2 + 2x - 2 – λ)/(x + 1)^2
The earlier observation now suggests that we trial is λ = 1 because the numerator in the derivative becomes
x^2 + 2x – 3 = (x – 1)(x + 3) giving dy/dx = 0 at x = 1 and x = -3.
The first value is the one we want, because it gives both slope zero and y = 0.
In other words the x axis is a tangent to C when λ = 1
I leave it to you to graph y = (x^2 – 2x - 4)/(x + 1), but y = 0 when
x^2 – 2x – 4 = 0 leading to x = 1 ± √5
Can you see videos on your mobile/PC?Thank you very much for your response.
Sorry for being repetitive, but I am still unsure of why we assume λ = 1
Please please make the description very detailed of why we do this, as I am self-learning and don't know the whole thing.
Yes!Can you see videos on your mobile/PC?
Will you be uploading one on the question?Can you see videos on your mobile/PC?
See that chapter here : http://www.examsolutions.net/maths-revision/syllabuses/Index/period-1/Further-Pure/module.phpWill you be uploading one on the question?
Look at these notes below n try ur self..Help please!!!!!!
Q1:Find the length of the arc of the parabola x=at^2, y=2at, between the points(0,0) and (ap^2,2ap)
Q2: Find the length of the arc of the cycloid x=a(t+sin t), y=a(1-cos t), between the points t=0 and t=pi
Does anybody feel the final integral hard to evaluate?
Polar coordinates and curves : http://examsolutions.net/maths-revision/syllabuses/Index/period-1/Further-Pure/module.phpFind the area of the surface generated by rotating about the x-axis for curve y=e^(3x), from x=1 to x=4
Just do your best. ^_^So just to clarify, how many percentage marks are you supposed to get in F Maths?
Because it is hell of a lot tougher than others where does the percentile end up?
1 / r(r + 1)(r - 1) = A/r + B/(r + 1) + C/(r - 1) such that the coefficients of terms in r² and r add to zero and the constant comes to 1.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics - Further (9231)/9231_w13_qp_13.pdf
Question 1. Completely lost. Help!
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