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Oh my god thank you so much. You're an angel. May God bless you. Have a good dayhere you go
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My question is that my sir said that when we are taking moments at A, there is no need to consider forces at C of AC on BC and vice versa. Why is this so? Why shouldnt we account for forces at C when taking moments at A? Is it bcoz at C, force of AC on AB and AB on AC would be equal and opposite that they would get cancelled. if this is the case, how can we be sure that the 2 forces at C are same?
Thanks
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I get it. Thanks for your helpYes, that is the case. We are essentially looking at resolved contact forces at C with vertical and horizontal components. Since the horizontal force exerted by one rod is equal and opposite to that of the other rod (action-reaction pair, 3rd Law) and same case for vertical components, the forces gets cancelled and need not to be taken when considering the WHOLE system!
View attachment 51090Cam someone please help me solve this...

thanks you very much
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