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There was a second part to the question? X_XAns was c. U had to form the second eq as well ... It was lyk dis - 2HCl+(i forgot the other reactant ) = --- + H2 . So mole ratio is 2:1. Whereas eq in the ques was - H2SO4+ (i dont know wat) = --- + H2. Hence mole ratio here is 1:1. So originally there were 0.02 mols of hydrogen gas
Yea there was, two different acids were involved - HCl n H2SO4T
There was a second part to the question? X_X
Dont worry, it was just 1 markT
There was a second part to the question? X_X
I marked no more hydrogen is producedWat was the ans to that MCQ in which there was a graph? I ticked the option which said - 'the rate of reaction is at its maximum'. Was dis the correct 1?
you are right. This was the answer, cuz the graph had become straightI marked no more hydrogen is produced
I marked no more hydrogen is produced
No, if no more hydrogen was produced, the graph would have came down to zero. It was the AMOUNT of hydrogen produced that had became constantyou are right. This was the answer, cuz the graph had become straight
No, if no more hydrogen was produced, the graph would have came down to zero. It was the AMOUNT of hydrogen produced that had became constant
I don't get it ... y-axis was labelled vol of hydrogen so a horizontal line will represent a constant vol of hydrogen being produced with the passage of timek you seem to be confused about reading graphs the y axis was labelled volume of hydrogen. When there is no increase in the y axis, it means there is no hydrogen being produced now. if it had been volume of hydrogen produced, you would have been right
it wont be aluminum since aluminum wont react easily either because of the oxide coating. the metal had to be "reactive" and aluminum isn't very reactive therefore it was magnesium, even the Ar confirmed it.
View attachment 25441
Anyway,history paper was really easy!I don't think anyone here would've found it difficult!
lets say that at the constant line, the volume of hydrogen was 50cm3. I think it was labelled volume of h2 collected or something like that. When the volume stops increasing, and becomes constant on 50cm3, there is no more h2 being producedI don't get it ... y-axis was labelled vol of hydrogen so a horizontal line will represent a constant vol of hydrogen being produced with the passage of time
ohhh now i get it ... damn it, a mark lostlets say that at the constant line, the volume of hydrogen was 50cm3. I think it was labelled volume of h2 collected or something like that. When the volume stops increasing, and becomes constant on 50cm3, there is no more h2 being produced
It went awesome.......alhough they did amend the question about the british control(1750-18500 by the way wht u wrote in thatView attachment 25441
Anyway,history paper was really easy!I don't think anyone here would've found it difficult!
yeah the vol of H2 became constant..lets say that at the constant line, the volume of hydrogen was 50cm3. I think it was labelled volume of h2 collected or something like that. When the volume stops increasing, and becomes constant on 50cm3, there is no more h2 being produced
Value of f is 10 cm.Now that 24 hours have passed, lets discuss the physics atp...what was your value of f? Also how could the problem of the voltage drastically decreasing be avoided (in the last question). And what precautions the student take to make his values of v as accurate as possible?
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