guys how fats are you supposed be to finish math p4?

[Igcse stuff]

can someone tell the fastest time to finish math p4?

 

[Prathmesh Thakkar]

can someone tell the fastest time to finish math p4?

2.5 hrs if u taking p4 else 2 hrs if u taking p 3

 

[Igcse stuff]

ayt thanks, i take p4 btw. now my question is how long are supposed to take, to finish in time before the exam is over?

 

[Fatima18]

ayt thanks, i take p4 btw. now my question is how long are supposed to take, to finish in time before the exam is over?

If you take around 12 minutes for each question then that would be great, since it will allow you to have approximately 30 minutes to revise.

 

[Igcse stuff]

If you take around 12 minutes for each question then that would be great, since it will allow you to have approximately 30 minutes to revise.

wow! now thats fast, and thanks for informing me

 

[Master Minds]

the time division depends on the questions in the paper. There are about 9-12 questions in paper usually and time taken for each question depends on your skills in the topic(s) being assessed and length. In my opinion, if you are fully prepared and confident you can complete the paper max 45 minutes before. SURPRISING BUT TRUE FROM MY EXPERIENCE!

 

[Igcse stuff]

that's true, although I feel drawing graphs is sometimes time consuming, together with sequences
otherwise, thanks

the time division depends on the questions in the paper. There are about 9-12 questions in paper usually and time taken for each question depends on your skills in the topic(s) being assessed and length. In my opinion, if you are fully prepared and confident you can complete the paper max 45 minutes before. SURPRISING BUT TRUE FROM MY EXPERIENCE!

 

[Fatima18]

that's true, although I feel drawing graphs is sometimes time consuming, together with sequences
otherwise, thanks

I think sequences are the worse.I just hateeeee them.

 

[Igcse stuff]

I think sequences are the worse.I just hateeeee them.

lets hope they don't come in the finals

 

[Igcse stuff]

does anyone have, igcse mathematics by karen morrison in pdf ? if you do, can you please upload it here on this thread

 

[Master Minds]

The sequences just test ur math logic and one answer can be deduced from the other part i.e. if you stuck in part (a) you may find the answer with the information in part (b) but not everytime. So the thing you need is the way to find nth term. In my opinion sequences will be a part of math upcoming p4 as they came before. BEST OF LUCK and hope u will cope with it

 

[Igcse stuff]

The sequences just test ur math logic and one answer can be deduced from the other part i.e. if you stuck in part (a) you may find the answer with the information in part (b) but not everytime. So the thing you need is the way to find nth term. In my opinion sequences will be a part of math upcoming p4 as they came before. BEST OF LUCK and hope u will cope with it

thanks a lot, and i've already coped with it, i've got no other choice

 

[OMakLL]

if any one needs help in sequences i can help and even any other topic

 

[asdfghj]

if any one needs help in sequences i can help and even any other topic

i do!! you got any notes for sequence??

 

[Igcse stuff]

yeah do you have notes?

if any one needs help in sequences i can help and even any other topic

 

[Master Minds]

apart from an+b formula for nth term, I have another long but easy mehtod which can give you the solution to any possible sequence. In igcse for most we get the sequences with difference in two generations if there is unequal difference i.e. sequence: 2, 4, 8, 14, 22....
differences: 2, 4, 6, 8, .....
final ratio/second difference: 2, 2, 2....
In such cases you may use variables in quadratic forms, as they are till second difference, to substitute the sequence terms. This is general substitution for all such sequences.
i.e. sequence: a+b+c, 4a+2b+c, 9a+3b+c, 16a+4b+c, 25a+5b+c....
differences: 3a+b, 5a+b, 7a+b, 9a+b
final ratio: 2a, 2a, 2a
Note that the coefficients depends on the quadratic term: an^2 + bn+ c, n becomes term number and a,b and c are variables.
so now once you are done with it, find the values of a,b and c like this:
2a= 2
a= 1

3a+b= 2
3(1) + b= 2 (putting value of a)
b= 2-3= -1

a+b+c= 2
1+ (-1) + c= 2
c= 2

so now putting the values in quadratic term an^2+bn+c
so the nth term is n^2-n+2 (factorise further if possible)
Once you fully understand and master the concept, there should be no prolem in number sequences.
Any question??

 

[Igcse stuff]

so you use one of these (a+b+c) ( 4a+2b+c)( 9a+3b+c)( 16a+4b+c)( 25a+5b+c) formulas to find which variables work best for a particular sequence and then use the equation (an^2+bn+c) right? or you think of an equation that can work bets with the variables in the sequence other than (an^2+bn+c)

apart from an+b formula for nth term, I have another long but easy mehtod which can give you the solution to any possible sequence. In igcse for most we get the sequences with difference in two generations if there is unequal difference i.e. sequence: 2, 4, 8, 14, 22....
differences: 2, 4, 6, 8, .....
final ratio/second difference: 2, 2, 2....
In such cases you may use variables in quadratic forms, as they are till second difference, to substitute the sequence terms. This is general substitution for all such sequences.
i.e. sequence: a+b+c, 4a+2b+c, 9a+3b+c, 16a+4b+c, 25a+5b+c....
differences: 3a+b, 5a+b, 7a+b, 9a+b
final ratio: 2a, 2a, 2a
Note that the coefficients depends on the quadratic term: an^2 + bn+ c, n becomes term number and a,b and c are variables.
so now once you are done with it, find the values of a,b and c like this:
2a= 2
a= 1

3a+b= 2
3(1) + b= 2 (putting value of a)
b= 2-3= -1

a+b+c= 2
1+ (-1) + c= 2
c= 2

so now putting the values in quadratic term an^2+bn+c
so the nth term is n^2-n+2 (factorise further if possible)
Once you fully understand and master the concept, there should be no prolem in number sequences.
Any question??

 

[TeenStar]

apart from an+b formula for nth term, I have another long but easy mehtod which can give you the solution to any possible sequence. In igcse for most we get the sequences with difference in two generations if there is unequal difference i.e. sequence: 2, 4, 8, 14, 22....
differences: 2, 4, 6, 8, .....
final ratio/second difference: 2, 2, 2....
In such cases you may use variables in quadratic forms, as they are till second difference, to substitute the sequence terms. This is general substitution for all such sequences.
i.e. sequence: a+b+c, 4a+2b+c, 9a+3b+c, 16a+4b+c, 25a+5b+c....
differences: 3a+b, 5a+b, 7a+b, 9a+b
final ratio: 2a, 2a, 2a
Note that the coefficients depends on the quadratic term: an^2 + bn+ c, n becomes term number and a,b and c are variables.
so now once you are done with it, find the values of a,b and c like this:
2a= 2
a= 1

3a+b= 2
3(1) + b= 2 (putting value of a)
b= 2-3= -1

a+b+c= 2
1+ (-1) + c= 2
c= 2

so now putting the values in quadratic term an^2+bn+c
so the nth term is n^2-n+2 (factorise further if possible)
Once you fully understand and master the concept, there should be no prolem in number sequences.
Any question??

This video explains that method. I use it as well.

 

[Igcse stuff]

i can't see the video, can you try uploading it again, i really want to see it

 

[Igcse stuff]

ok i see it now thanks