Guyzz lotzz of Chemistry doubtzz plzz take a loke if u can help

[Abhi Mevawala]

plzz help this r my doubtzz

 

[Abhi Mevawala]

a few more

 

[Namehere]

Could you atleast indicate the year the questions are from please?

 

[Abhi Mevawala]

y the answers r already there
still thy r combination of M/J/11 M/J/12 O/N/02 O/N/03 O/N/04 and O/N/05

 

[snowbrood]

plzz help this r my doubtzz

for pic 1
lets consider the number of moles for 1 mole of aluminium compound
72/24 gives 3 moles of number of moles of carbon should be 3
now come to aluminium balance the oxidation number of both elements so that net charge is 0
(3*x)+(4*3)=0 oxidation number of Al is +3

 

[snowbrood]

for pic 2
mole fraction= number of moles of a product/totalnumber of moles of products
so given this if ethene is 0.5 it means ethene is 50% of the total products
so the remaining two are 25% and 25% respectively
convert these so that we have the whole numbers(0.5*4 )=2 moles of ethene
0.25*4=1 moles of propene and methane
just add up the carbon atoms and hydrogen atoms to see which answer is correct

 

[snowbrood]

for qno3 any substance that undergoes a change in oxidation number is basically undergoing redox reaciton .
NaOcl is a bleaching solution that u have to know its in coursebook
since the final product has an halogen so it would give a ppt with silver nitrate
A is the answer

 

[snowbrood]

for q 4
the greater the interaction(or attraction) between molecules the more the gas deviates from ideal behavior as the temperature is constant so the gas cant liquify the answer is D please do tell me if this is the case

 

[snowbrood]

for q5
dipole is electrons in the bond spending more time around one atom than the other. this is due to electronegitivty differences so lets see which is most polar . bear in mind that methyl and h atoms are not much electronegative . O is one of the most electronegative element. A and D are not polar as there electronic density is spread symmetrically.A has no electronegitve element while the D does have Cl electronegative element but they are on both carbon atoms so net dipole.
so lets see B and C. B has greater electronegativity difference thus more dipole moment .due to the fact O is electronegative while the methyls arent that electronegative. O and Cl both are electronegitve in C so the difference is low and so the overal dipole. see it is easier for a heavier person (around 100kg) to pull (aroung 10kg) however it would be difficult for him to pull that fast a person weighing aroung 80kg

 

[snowbrood]

for q6
cracking is breaking the bigger molecules into smaller molecules
if u see the Octene has 8 C atoms so we should get exactly 8C
only B seems to be correct.

for q8
2 moles of HI GIVES 1 mole of I2 and H2 respectively
x number of moles HI wil give x/2 moles of these products

2HI(g) H2(g) + I2(g)
number of moles at the start b 0 0
moles at equilibrium b-x x/2 x/2
(x/2)*(x/2)/(b-x)^2
x^2/4(b-x)^2 is the answer that is D

 

[Abhi Mevawala]

thnxx hlped me a lot
plzz see othes if possible

 

[DumbIdiot]

for num 6 all 4 molecules can be obtained from cracking.
the question didnt ask for molecules whose total number of C adds up to 8
all four can be obtained during different reactions.( actually all hydrocarbon having less than 8 carbons can be obtained, no branch since the original is straight)

 

[DumbIdiot]

question 7 is kinda different but the reaction seems possible
the answer must be D
the NH3 firstly replaces br in either c1 or c5
now this resulting -NH2 group replaces the br in the other carbon by the same reaction( its like reacting CH3nh2 with ch2ch2br. one h atom atom in NH3 is substituted by an alkyl group which has little, if at all, effect in the way the amine group reacts.)