hey .. can anyone help me !! in core 1

[DANGERBP]

i need all the formulas that we need ... (volume plus surface area ) thts it
thx
much apreciated !!

 

[étudiante]

wat formulas? u need all da basic 1s frm o lvls dats it!

 

[DANGERBP]

wat formulas? u need all da basic 1s frm o lvls dats it!

ya ... which r .. =p

 

[étudiante]

i dont remember da list acc..... sowieeee...... been a yr now! but i can say dey were just basic 1s which u will remember neway

 

[DANGERBP]

i dont remember da list acc..... sowieeee...... been a yr now! but i can say dey were just basic 1s which u will remember neway

ya thnk you anyways vmuch =)

 

[badrobot14]

Volumes:
For any regular figure (prism, cuboid, cylinder): base area * height
pyramid: (1/3)*base area*height
Cone: (1/3)*base area*height = (1/3)*pi r^2*height

 

[badrobot14]

http://ruchi-mathematics.blogspot.com/2011/06/mensuration-formula.html

 

[DANGERBP]

http://ruchi-mathematics.blogspot.com/2011/06/mensuration-formula.html

thank youuu !! so much
hey would you happen to know how to solve this ..
maximum value of f(x)
when f(x)=9-(x-2)^2

 

[badrobot14]

thank youuu !! so much
hey would you happen to know how to solve this ..
maximum value of f(x)
when f(x)=9-(x-2)^2

easy; take it's derivative.. at max value, derivative (or slope) = 0
i.e. f'(x) = 0
sove that equation to get x=something

put this value of x in f(x)=9-(x-2)^2 to get f(x) = the max value...

 

[DANGERBP]

easy; take it's derivative.. at max value, derivative (or slope) = 0
i.e. f'(x) = 0
sove that equation to get x=something

put this value of x in f(x)=9-(x-2)^2 to get f(x) = the max value...

thank you ... =) =)