How did Maths 12 go? No discussion

[farhan141]

Same. I wrote all real numbers..

Yea but I wasn't getting set of values...

 

[hacker]

Anyone who remembers what the shaded area region expression was in terms of r and theta
and how did u exactly calculated radius of semicirle in terms of r ?

I used trig ratios by bisecting the angle and then applying sinO then formed the expression of radius of semicircle in terms of r
then AREA of SEMICIRCLE + area of triangle -(area of sector)

please do reply with your workings :|

 

[farhan141]

Radius was rsinTheta

The whole answer I don't rly remember.

But yes method was what u used.

 

[DeadlYxDemon]

What ans u got for the first Q? The f (x) one?

 

[DeadlYxDemon]

The formula in that Shaded Region Q
Wasn't it like Area of Semicircle - (area of arc + area of Segment) ?? :/

 

[<><> Ice <><>]

for the time question
I gave the answer as 10<t<20 T_T
why why why why 'I misunderstood the question

 

[pakhee]

I got p is less than half in set of values.Anyone else?

 

[pakhee]

Q.6 (i) h=120m
(iii) t=10 min

Credits: Sir Mehboob

How did you do part ii?To show k.

 

[asadalam]

Same. I wrote all real numbers..

p<0.5

Apply the discriminant using

6^2 - 4(i dont exactly remember x value)(5-p)<0

It would give the range to be p<0.5
I even checked on my calculator to be sure

The binomial one,were the first answers 240x^2 and -160x^3 and the second ans 540x^3?

 

[asadalam]

sum to infinity ?

54

 

[pakhee]

for area,i did area of semicircle minus (area of sector minus triangle)

 

[asadalam]

for area,i did area of semicircle minus (area of sector minus triangle)

Same

 

[pakhee]

p<0.5

Apply the discriminant using

6^2 - 4(i dont exactly remember x value)(5-p)<0

It would give the range to be p<0.5
I even checked on my calculator to be sure

The binomial one,were the first answers 240x^2 and -160x^3 and the second ans 540x^3?

yes,i got those too.For infinity i got 54 as well.

 

[asadalam]

yes,i got those too.For infinity i got 54 as well.

What values did you get for the triginometry q?Tan theta?

 

[farhan141]

I'm losing total of 10-12 marks

 

[asadalam]

I'm losing total of 10-12 marks

where?

 

[pakhee]

one was 71.56 and the other 108.r.Tan theta was plus-minus 3.

 

[farhan141]

Can u tell me two values of c in 2nd part of integration question? Also does anyone remember the tanTheta question?

 

[asadalam]

Can u tell me two values of c in 2nd part of integration question? Also does anyone remember the tanTheta question?

Values of c were 2.5 and -3.5 .I got that tan theta one wrong im sure as my ans were for tan=-1 and 6 somehow so i got 80.5 and 135.Im sure those are wrong though.Did you manage to prove that trig identity?

 

[pakhee]

in the very first question was c=8?